The commutative property implies that, the order of multiplication is not important.
is true
Commutative property of multiplication states that:
If 
The expression is given as:
To get the commutative expression, we simply change the position of each factor in the expression.
So, some possible equivalent expressions are:
There are several other equivalent expressions.
From the list of options;
is true
Read more about commutative property at:
brainly.com/question/7037119
Answer:
Right-triangle
Step-by-step explanation:
Take a right triangle for example, then twist it 360 degrees, keeping the longest leg at the center of rotation. It will then form a cone.
Answer:
you need to rotate this angle and by the theme they give either by clockwise or anti-clockwise because this image here is rotational.
Answer and Step-by-step explanation:
(a) Given that x and y is even, we want to prove that xy is also even.
For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.
(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:
Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.
(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.
Answer:
If your problem looks like this (in the picture) then the answer is D.
Step-by-step explanation:
Hope this helps and is the question and answer your looking for!?
