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vladimir2022 [97]
3 years ago
11

81,924+3,827 equals

Mathematics
2 answers:
ladessa [460]3 years ago
7 0
85,651 i think double check i did the math in my head
mixas84 [53]3 years ago
6 0

Answer:

85751

Step-by-step explanation:

81924

+ 3827

_______

 85751


- Start from the right side, 4 + 7 = 11, but the 1 is carried over

- 2 + 2 + 1 = 5

- 9 + 8 = 17, but the 1 is carried over

- 1 + 3 + 1 = 5

- 8 + 0 = 8

Thus, the answer becomes 85751.

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It is known that 10% of adults can pass a fitness test. What notation would be used to describe a count of the number of adults
Andrej [43]

Answer:  B. x ~ B(50, .1)

In other words, it's the second answer choice

===========================================================

Explanation:

We have n = 50 people in the sample and p = 0.10 is the decimal form of 10%, to represent the probability of success. In this case, we define "success" as "the person passes the fitness test".

The random variable x is the count of how many people pass. So we could have x = 0, x = 1, x = 2, ..., x = 49, x = 50. Basically any whole number from 0 to 50 inclusive. Furthermore, x is approximately modeled by the binomial distribution which we denote as B(n, p) = B(50, 0.1)

So X ~ B(50, 0.1)

3 0
3 years ago
Multiply. (w-7) (w+4)
stira [4]

Use the FOIL (first, outside, inside, last) to expand the terms in the brackets.

(w - 7)(w + 4)

first: w × w = w²

outside: w × 4 = 4w

inside: -7 × w = -7w

last: -7 × 4 = -28

Now you add all the terms together to get:

w² + 4w - 7w - 28

This simplifies to give you:

w² - 3w - 28

Hope that helps! :)

5 0
3 years ago
The length of a rectangle is 6 more than twice its width. The perimeter of the rectangle is 108, what are the dimensions of the
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An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 75 type K batteries and a sample of 46
lorasvet [3.4K]

The decision rule for rejecting the null hypothesis, considering the t-distribution, is of:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means is of zero, hence:

H_0: \mu_1 - \mu_2 = 0

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means different of zero, hence:

H_1: \mu_1 - \mu_2 \neq 0

We have a two-tailed test, as we are testing if the mean is different of a value.

Considering the significance level of 0.05, with 75 + 46 - 2 = 119 df, the critical value for the test is given as follows:

|t| = 1.9801.

Hence the decision rule is:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

More can be learned about the t-distribution in the test of an hypothesis at brainly.com/question/13873630

#SPJ1

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