Answer:
6 + (d * 2)
Step-by-step explanation:
You are adding 6 to the equation after the amount d times 2. In that case, a parentheses is required to round up d * 2.
Answer:
![E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}](https://tex.z-dn.net/?f=E%28X%29%3D%20n%20%5Cint_%7B0%7D%5E1%20x%5En%20dx%20%3D%20n%20%5B%5Cfrac%7B1%7D%7Bn%2B1%7D-%20%5Cfrac%7B0%7D%7Bn%2B1%7D%5D%3D%5Cfrac%7Bn%7D%7Bn%2B1%7D)
Step-by-step explanation:
A uniform distribution, "sometimes also known as a rectangular distribution, is a distribution that has constant probability".
We need to take in count that our random variable just take values between 0 and 1 since is uniform distribution (0,1). The maximum of the finite set of elements in (0,1) needs to be present in (0,1).
If we select a value 
we want this:
And we can express this like that:
for each possible i
We assume that the random variable 
are independent and 
from the definition of an uniform random variable between 0 and 1. So we can find the cumulative distribution like this:
And then cumulative distribution would be expressed like this:
For each value 
we can find the dendity function like this:
So then we have the pdf defined, and given by:
and 0 for other case
And now we can find the expected value for the random variable X like this:
Answer:
2/5
Step-by-step explanation:
3/5 / 2/3
3/5 ÷ 2/3
Convert ÷ sign into multiplication, that will turn 2/3 into 3/2
3/5 X 2/3
Divide by 3
3/5 by 3
1/5
2/3 by 3
2/1
1/5 X 2/1
2/5
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -15 ± √((15)^2 - 4(2)(4)) ] / ( 2(2) )
x = [-15 ± √(225 - (32) ) ] / ( 4 )
x = [-15 ± √(193) ] / ( 4)
x = [-15 ± sqrt(193) ] / ( 4 )
x = -15/4 ± sqrt(193)/4
The answers are -15/4 + sqrt(193)/4 and -15/4 - sqrt(193)/4.
