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3 years ago

According to Coulomb's Law, if the distance between the two electrons were cut in half, the force would be _____.

Physics

1 answer:

Alika [10]3 years ago

8 0

Answer:

Explanation:

The force is quardrupled when the distance between the two electrons are cut.

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Johnny walked to the other side of his building using the following steps: 10 meters North, 20 meters to the West, 40 meters Sou

nataly862011 [7]

Answer:

Distance traveled = 70 meters

Displacement = 36.06 meters

Explanation:

Let north be positive Y and east be positive X

10 meters north, displacement = 10 j meters

20 meters west, displacement = -20 i meters

40 meters south, displacement = -40 j meters

Total displacement = (10 j - 20 i – 40 j) meters = (- 20 i - 30 j) meters

Magnitude of displacement = $\sqrt{20^2+30^2}=\sqrt{1300}= 36.06 meters$

Distance traveled = 10+20+40 = 70 meters

6 0

4 years ago

What is the amplitude of a wave related to

Vanyuwa [196]

Answer:

intensity because square of the amplitude is proportional to the intensity of the wave

Explanation:

3 0

3 years ago

Read the list of phrases from the article.

ICE Princess25 [194]

Answer:

(D)

to establish an understanding of key concepts relating to population biology

Explanation:

Thats what I would go with but I didn't read the article so I don't know what context was used. Good luck! :)

8 0

3 years ago

Regular exercise is positively related to wellness

Harman [31]

Answer:

yes ( true)

Explanation:

positive effects on all the body systems.

7 0

3 years ago

Suppose you first walk 12.0 m in a direction 20? west of north and then 20.0 m in a direction 40.0? south of west. how far are y

Gnesinka [82]

The representation of this problem is shown in Figure 1. So our goal is to find the vector $\overrightarrow{R}$ . From the figure we know that:

$\left | \overrightarrow{A} \right |=12m \\ \\ \left | \overrightarrow{B} \right |=20m \\ \\ \theta_{A}=20^{\circ} \\ \\ \theta_{B}=40^{\circ}$

From geometry, we know that:

$\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}$

Then using vector decomposition into components:

$For \ A: \\ \\ A_x=-\left | \overrightarrow{A} \right |sin\theta_A=-12sin(20^{\circ})=-4.10 \\ \\ A_y=\left | \overrightarrow{A} \right |cos\theta_A=12cos(20^{\circ})=11.27 \\ \\ \\ For \ B: \\ \\ B_x=-\left | \overrightarrow{B} \right |cos\theta_B=-20cos(40^{\circ})=-15.32 \\ \\ B_y=-\left | \overrightarrow{B} \right |sin\theta_B=-20sin(40^{\circ})=-12.85$

Therefore:

$R_x=A_x+B_x=-4.10-15.32=-19.42m \\ \\ R_y=A_y+B_y=11.27-12.85=-1.58m$

So if you want to find out how far are you from your starting point you need to know the magnitude of the vector $\overrightarrow{R}$ , that is:

$\left | \overrightarrow{R} \right |=
\sqrt{R_x^2+R_y^2}=\sqrt{(-19.42)^2+(-1.58)^2}=\boxed{19.48m}$

Finally, let's find the compass direction of a line connecting your starting point to your final position. What we are looking for here is an angle that is shown in Figure 2 which is an angle defined with respect to the positive x-axis. Therefore:

 $\theta_R=180^{\circ}+tan^{-1}(\frac{\left | R_y \right |}{\left | R_x \right |}) \\ \\ \theta_R=180^{\circ}+tan^{-1}(\frac{1.58}{19.42}) \\ \\ \theta_R=180^{\circ}+4.65^{\circ}=185.85^{\circ}$

6 0

4 years ago