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Soloha48 [4]
3 years ago
12

ASAP please!! The force vectors on an aircraft are as shown. Find the net (resultant force).

Physics
1 answer:
ioda3 years ago
6 0

Answer:

The magnitude of the net force is 5430N

Explanation:

I suggest to define the axes as aligned to the axis of the plane. This will require you to decompose only one vector, namely the Weight. We need two components of the W force: one in horizontal direction of the plane, the other perpendicular to it. Through a simple triangle argument you will se that the plane-horizontal component of W is

W_D=3600 N\cdot\sin 27^\circ=1634N

acting in the direction of the Drag, and the plane-perpendicular component is:

W_L=-3600N\cdot\cos 27^\circ=-3208N

with negative sign since it counteracts the Lift.

So the components of the netforce F are:

F_h=T-D-W_D=(8000-1000-1634)N=5366N\\F_v=L+W_L=(4100-3208)N=829N

The magnitude of the  net force is:

|F|=\sqrt{5366^2+829^2}N = 5430N


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Read 2 more answers
Please help ASAP!!
inessss [21]

Answer:

at t=46/22, x=24 699/1210 ≈ 24.56m

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The general equation for location is:

x(t) = x₀ + v₀·t + 1/2 a·t²

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x₀ is the starting position. At the base of the cliff we'll take x₀=0 and at the top x₀=46.0

v₀ is the initial velocity. For the ball it is 0, for the stone it is 22.0.

a is the standard gravity. In this example it is pointed downwards at -9.8 m/s².

Now that we have this formula, we have to write it two times, once for the ball and once for the stone, and then figure out for which t they are equal, which is the point of collision.

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Stone: x(t) = 0 + 22·t - 1/2*9.8 t²

Since both objects are subject to the same gravity, the 1/2 a·t² term cancels out on both side, and what we're left with is actually quite a simple equation:

46 = 22·t

so t = 46/22 ≈ 2.09

Put this t back into either original (i.e., with the quadratic term) equation and get:

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