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GalinKa [24]
2 years ago
9

Calculate the slope of the line on the graph using the formula:

Physics
1 answer:
gulaghasi [49]2 years ago
7 0

Answer:

The standard form of a straight line is

y = m x + b   where m is the slope

m = (y2 - y1) / (x2 - x1)

if the ordinate is formed by v instead of y then

m = (v2 - v1) / (x2 - x1)   normally for constant acceleration the slope is

(v2 - v1) / (t2 - t1) = a = m

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In the diagnostic radiology energy range (which includes mammography) from 23 to 150 kVp, which of the following tissues possess
Semmy [17]

Answer:

Bone

Explanation:

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The voltages used in diagnostic tubes range from roughly 20 kV to 150 kV and thus the highest energies of the X-ray photons range from roughly 20 keV to 150 keV.

The tests and equipment used sometimes involves low doses of radiation to create highly detailed images of an area.

4 0
3 years ago
A rock thrown straight up takes 4.2 s to reach its maximum height what was its initial velocity
liubo4ka [24]

Consider the upward direction of motion as positive and downward direction of motion as negative.

a = acceleration due to gravity in downward direction = - 9.8 \frac{m }{s^{2}}

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t = time to reach the maximum height = 4.2 sec

Using the kinematics equation

v = v₀ + a t

inserting the values

0 = v₀ + (- 9.8) (4.2)

v₀ = 41.2 \frac{m }{s}


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3 years ago
What does the power of a machine measure?
GarryVolchara [31]

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3 years ago
Read 2 more answers
A 72.9-kg base runner begins his slide into second base when moving at a speed of 4.02 m/s. The coefficient of friction between
elena-14-01-66 [18.8K]

Answer:

-589.05 J

Explanation:

Using work-kinetic energy theorem, the work done by friction = kinetic energy change of the base runner

So, W = ΔK

W = 1/2m(v₁² - v₀²) where m = mass of base runner = 72.9 kg, v₀ = initial speed of base runner = 4.02 m/s and v₁ = final speed of base runner = 0 m/s(since he stops as he reaches home base)

So, substituting the values of the variables into the equation, we have

W = 1/2m(v₁² - v₀²)

W = 1/2 × 72.9 kg((0 m/s)² - (4.02 m/s)²)

W = 1/2 × 72.9 kg(0 m²/s² - 16.1604 m²/s²)

W = 1/2 × 72.9 kg(-16.1604 m²/s²)

W = 1/2 × (-1178.09316 kgm²/s²)

W = -589.04658 kgm²/s²

W = -589.047 J

W ≅ -589.05 J

4 0
3 years ago
Which statements accurately describes the waste generated by nuclear reactions ? check all that apply.
Neko [114]
A) its 's hazardous for hundreds to thousand of year B) Some waste can be recycled and used again is the answer
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3 years ago
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