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Mandarinka [93]
3 years ago
13

What’s is 2000+100.000

Mathematics
2 answers:
Agata [3.3K]3 years ago
4 0

Answer:

2,100.000

Step-by-step explanation:

Margaret [11]3 years ago
3 0

Answer:

2000+100.000=2100

Its simple just calculate it in a calculator...

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can u tell me which letter the answer is.. i know how to do this problem im just confused what the answer is​
Ede4ka [16]

Answer:

Im pretty sure its a :3

Step-by-step explanation:

7 0
2 years ago
The function h(t) = −16t2 + 18t models the height, in feet, reached by a leopard t seconds after it jumps. What is the approxima
S_A_V [24]

9514 1404 393

Answer:

  5 1/16 ft

Step-by-step explanation:

  h(t) = -16t(t -18/16) . . . . put in intercept form

The function describes a parabola that opens downward. It has zeros at t=0 and t=9/8. The maximum height will be found at the vertex of the parabola, halfway between these zeros.

  f(9/16) = (-16)(9/16)² +18(9/16) = 81/16 = 5 1/16 . . . . feet

The approximate maximum height of the leopard is 5 1/16 feet.

5 0
3 years ago
Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
What is the solution to this equation x-16=-8
arsen [322]
X-16=-8
Add 16 on both sides 
x=-8+16
And solve; your answer will be
x=8
3 0
2 years ago
Find positive integers that satisfy
tankabanditka [31]

9514 1404 393

Answer:

  (x, y, z) = (1, 2, 3)

Step-by-step explanation:

The equations that result from reduction to row-echelon form are ...

  x = 0.4 +0.2t

  y = 5.6 -1.2t

  z = t

Then t must have a value 5n+3 for 0 ≤ n < 1. That is, t=3.

  x = 0.4 +0.2(3) = 1

  y = 5.6 -1.2(3) = 2

  z = 3

The integers that satisfy are (x, y, z) = (1, 2, 3).

4 0
3 years ago
Read 2 more answers
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