2 years ago

The expression (x2 + 16x + 64) – (x + 8)(x – 4) can be rewritten as k(x + 8). What is the value of k? k =

1 answer:

5 0

$expanding \\ {x}^{2} + 16x + 64 - ( {x}^{2} + 4x - 32) \\ distributing \: - 1 \\ {x}^{2} + 16x + 64 - {x}^{2} - 4x + 32 \\ 12x + 96 \\ take \: a \: factor \: of \: 12 \\ 12(x + 8) \\ so \: k = 12$

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AleksandrR [38]

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3 years ago

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Step-by-step explanation:

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3 years ago

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