Question

The expression (x2 + 16x + 64) – (x + 8)(x – 4) can be rewritten as k(x + 8). What is the value of k? k =

Answer 1

$expanding \\ {x}^{2} + 16x + 64 - ( {x}^{2} + 4x - 32) \\ distributing \: - 1 \\ {x}^{2} + 16x + 64 - {x}^{2} - 4x + 32 \\ 12x + 96 \\ take \: a \: factor \: of \: 12 \\ 12(x + 8) \\ so \: k = 12$