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Snowcat [4.5K]
3 years ago
10

The expression (x2 + 16x + 64) – (x + 8)(x – 4) can be rewritten as k(x + 8). What is the value of k? k =

Mathematics
1 answer:
9966 [12]3 years ago
5 0

expanding \\  {x}^{2}  + 16x + 64 - ( {x}^{2}  + 4x - 32)  \\ distributing \:  - 1 \\  {x}^{2}  + 16x + 64 -  {x}^{2}  - 4x + 32 \\ 12x + 96 \\ take \: a \: factor \: of \: 12 \\ 12(x + 8) \\ so \: k = 12
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Which table represents a linear function?
AlladinOne [14]

The rate of change for the function on the table is; 15 grapes eaten per minute.

<h3>What is the rate of change of the function described by the table?</h3>

It follows from the complete question that the table given indicates that;

  • after 1min, 15 grapes had been eaten,

  • after the next minute, 30 grapes had eaten,

  • after the 3rd minute, 45 grapes had already been eaten.

On this note, it is conclusive that the rate of change of the function represented by the table is; 15 grapes eaten per minute.

Read more on rate of change;

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4 0
2 years ago
The value of x is? also can you explain how to do this?
jek_recluse [69]
We have to know the angle that is not labelled. (lets call it y) 
9x + y= 180 

and the sum of the angles of a triangle is 180 
5x + (9+x) + y=180 

2 simultaneous equations 
6 0
3 years ago
Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy
Alborosie

Answer:

H 0 : μ = 3.1    H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66

df = n-1=75-1 =74

The p value is:

p_v = P(t_{74} >8.66) =3.65x10^{-13}

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1    H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

\bar X = 3.13 , s =0.03 , n =75

The statistic to check the hypothesis is given by:

t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}

Replacing the info given we got:

t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66

The degrees of freedom are given by:

df = n-1=75-1 =74

The p value since is a right tailed ted is given by:

p_v = P(t_{74} >8.66) =3.65x10^{-13}

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0
3 years ago
Each face of a number cube is a square with a side length of 16 millimeters. What is the total area of all of the faces of the n
kupik [55]

Answer:

1536² mm

Step-by-step explanation:

16 x 16 = 256

256 x 6 = 1536 (6 = number of faces)

1536²mm

6 0
2 years ago
Solve 15n &gt; 12n + 18
gogolik [260]
15n > 12n + 18
3n > 18
n > 6
3 0
3 years ago
Read 2 more answers
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