Answer:
Assciates Property
Step-by-step explanation:
look at the picture above
Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
To find slope, use the equation (y2-y1)/(x2-x1). In your case, the equation is going to look like (-3 - -1)/(5 - -2) or (-3 +1)/(5 + 2), and that simplifies to -2/7.
-4 = x - 7
-4 + 7 = x
3 = x
Therefore x = 3