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IrinaK [193]
3 years ago
11

Jenny bought a new car for $25,995. The value of the car depreciates by 16 percent each year. Which type of function could model

the value of the car? A. Exponential B. Can't be determined C. Linear D. Quadratic
Mathematics
2 answers:
Vlada [557]3 years ago
8 0

Answer:

an exponential function

Step-by-step explanation:

Use a function of the same form as the compound amount formula:

A = P(1+r)^5, where r is the appreciation or depreciation rate and P is the initial value.  This is definitely an exponential function.

motikmotik3 years ago
6 0

Answer: The answer is expensive the car is expensive. JK the answer is c. you can eliminate a and d because the 16 % a year increase so your left with c and b it's not b because of the price so your best answer would have to be c

hoped this helped lol have a good day

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You can rewrite the given log expressions to express them in terms of ln(a), ln(b), and ln(c). Then substituting the given values will produce the value of the expression.

Or, you can define the variables 'a', 'b', and 'c' and let your calculator compute these directly.

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<h3>1.</h3>

  \ln\left(\dfrac{a^4}{b^4c^{-2}}\right)=4\ln(a)-(4\ln(b)-2\ln(c))=4\cdot2-4\cdot3+2\cdot5=\boxed{6}

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  \ln\left(\sqrt{b^{-2}c^4a^2}\right)=\dfrac{1}{2}\left(-2\ln(b)+4\ln(c)+2\ln(a)\right)=\ln(a)-\ln(b)+2\ln(c)\\\\=2-3+2\cdot5=\boxed{9}

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  \dfrac{\ln(a^1b^2)}{\ln(bc)^2}=\dfrac{\ln(a)+2\ln(b)}{(\ln(b)+\ln(c))^2}=\dfrac{2+2\cdot3}{(3+5)^2}=\dfrac{8}{64}=\boxed{\dfrac{1}{8}}

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_____

The applicable rules of logarithms are ...

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7 0
2 years ago
A farmer wants to build a rectangular pen and then divide it with two interior fences. The total area inside of the pen will be
irina [24]

Answer:

Dimensions of the pen:

x = 11 ft

y = 6 ft

Step-by-step explanation:

Let call "x"  and "y"  dimensions of the rectangular pen  and  x > y, so the interior fences will be equal to y.

The exterior length is 2*x + 2*y and its cost is (2*x + 2*y ) *20.40

The interior fences are 2*y  and its cost is 2*y* 17

Total cost C  = (2*x + 2*y ) *20.40 +  2*y* 17       (1)

Now area inside the pen is 66 ft²  and it is equal to:

A = x*y    ⇒  66 = x*y   ⇒  y = 66/x

Plugging that value in equation (1) will give C as a function of x

C(x) = [ 2*x + 2* (66/x) ]* 20.40  +  2* (66/x) * 17

C(x) = ( 2*x + 132/x ) 20.40  +  2244/x

C(x)  = 40,80*x + 2692.8/x  + 2244/x

C(x) = 40.80*x  + 4936,8/x

Taking derivatives on both sides of the equation we get

C´(x)  = 40.80 - 4936,8/x²

C´(x)  = 0    ⇒   40.80 - 4936,8/x² = 0   ⇒  40.80 *x² = 4936,8

x² =  4936,8 / 40.80    ⇒  x²  = 121  ⇒  x √121

x = 11 ft

And  y = 66/x   ⇒  y  = 66/11    ⇒  y = 6 ft

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