Question

In a hypothetical situation, B is the allele that causes brachydactyly. If a man who has normal fingers (bb) and a woman with brachydactyly (Bb) have children, what proportion of these children would you expect to have normal fingers? (Hint: Use a Punnett square).

Answer 1

Answer:

2 in 4 children will have normal finger

Explanation:

a cross between the gene for normal finger bb and the gene for brachdactyly Bb will give the result below;

Bb, bb, Bb and bb.

thus 2 in the 4 have normal fingers.