Write an integer to represent the following situation: Earnings 15 dollars

Andreas93 [3]

A. there are 72 right-handed batters. this is what you do:
5:8
45:?
45/5=9
8*9=72 so
45:72
b. there are 45 left-handed batters
the total batters is 45+72=117
so the ratio of left-handed to the total batter would be 45:117
hope this helps :)

4 0

3 years ago

Steve and Michelle Neely are celebrating their 30th anniversary by having a reception at a local reception hall. They have budge

lord [1]

4 500-60 = 4 440
4 440/38 = 116.8
At most they would be able to invite 116 people to the reception with their budget.

8 0

3 years ago

Read 2 more answers

Suppose a local manufacturing company claims their production line has a variance of less than 9.0. A quality control engineer d

Alexxx [7]

Answer:

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

$p_v =P(\chi^2$

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=35$ represent the sample size

$\alpha=0.01$ represent the confidence level

$s =2.12$ represent the sample deviation obtained

$\sigma_0 =3$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is lower than 9 and the deviation lower than 3, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 9$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case df= n-1= 35-1=34. And since is a left tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(16.979,34,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

6 0

3 years ago

HELP!! T.T This is due tonight!!!

lesya [120]

D and e would be the answer

3 0

3 years ago

Which of the following is the graph of:<br>(x-3)^2+(y+1)^2=9?

Marianna [84]

<h3>Answer: Choice A</h3>

center = (3, -1)

radius = 3

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Explanation:

Rewrite the y+1 as y-(-1). Rewrite the 9 as 3^2

Then compare to the general form (x-h)^2+(y-k)^2 = r^2

You should find that h = 3, k = -1 and r = 3.

The center is (h, k) = (3,-1) and the radius is r = 3.

Choice A matches with that description.

8 0

2 years ago