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gogolik [260]
3 years ago
14

Solve for n: n + (-20) = 22 A. 2 B. -42 C. 44 D. None of the above

Mathematics
2 answers:
kifflom [539]3 years ago
8 0
D 44-20=22 so yea i need 20 characters so i’m still typing
klasskru [66]3 years ago
7 0

- N = 42

Since that's not really an answer choice then your best bet is to choose 'D'.

<em>- Ouma</em>

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Distance, Midpoint, Circles - What is the equation of the circle? WILL GIVE BRAINLIEST!
elixir [45]

Answer:

(x-4)^2 + (y-3)^2 =8

Step-by-step explanation:

The midpoint of the diameter is (6+2)/2= 4, (5+1)/2 = 3

(4,3)

The radius is the distance from the midpoint to an endpoint

This is 2sqrt(8)

So the equation is

(x-4)^2 + (y-3)^2 =8

5 0
3 years ago
22x – 54 + 5.736x^4 - 2x^2<br> Standard form
Yuri [45]

Answer:

5.736x^4 - 2x^2 +22x - 54

Step-by-step explanation:

4 0
3 years ago
Brandy has a new part-time job. On Monday, she worked 8 hours. On Wednesday, she worked three-fourths as long as she did on Mond
Setler79 [48]

Answer:

both of them are odd (because both of them are even, the reverse would be true)

Step-by-step explanation:

if she worked 8 on Monday, and on Wednesday worked for 3/4ths that amount of time she would've worked 6 hours. So an UNTRUE statement about this would be that they're both odd.

8 0
3 years ago
Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams
hram777 [196]

Answer:

X(16)=25.71grams

Step-by-step explanation:

let X(t) denote grams of C formed in  t mins.

For X grams of C we have:

\frac{2}{3}Xg of A and \frac{1}{3}Xg of B

Amounts of A,B remaining at any given time is expressed as:

40-\frac{2}{3}Xg of A and  50-\frac{1}{3}Xg  of B

Rate at which C is formed satisfies:

\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt  \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}

Apply the initial condition,X(0)=0 ,to the expression above

0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}

Now at X(8)=15:

15=90-\frac{90}{90\times 8k+1}  \ ->75=\frac{90}{720k+1}\\k=0.0002778

Substitute  in X(t) to get

X(t)=90-\frac{90}{0.0002778t\times 90+1}\\X(t)=90-\frac{90}{0.25t+1}\\But \ t=16\\\therefore X(t)=90-\frac{90}{0.025\times16+1}\\X(t)=25.71

5 0
3 years ago
What is g(x)?<br> A. g(x) = -2<br> B. g(x) = -x<br> C. g(x) = -|x|<br> D. g(x) = -x^2
Nastasia [14]

Answer:

A. g(x) = -2^x.

Step-by-step explanation:

If g(x) = -2, it would be a straight line running horizontally.

If g(x) = -x, it would be a linear equation.

If g(x) = -|x|, it would be an absolute value function, which is a graph in a v-shape.

So, the remaining answer is that A. g(x) = -2^x.

Hope this helps!

3 0
3 years ago
Read 2 more answers
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