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Marizza181 [45]
3 years ago
7

How do you solve those two problems?

Mathematics
2 answers:
Rom4ik [11]3 years ago
8 0
I hope this helps you

Likurg_2 [28]3 years ago
8 0
Divide if it has a decimal
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−−→ LO bisects ∠ NLM , LM = 18 , NO = 4 , and LN = 10 . LO → bisects ∠ NLM , LM = 18 , NO = 4 , and LN = 10 . What is the value
Sindrei [870]

Answer:

7.2

Step-by-step explanation:

Given that in triangle LMN, LO is angle bisector of angle L.

LN =10 and LM =18

By angle bisector theorem for triangles we have

LN/LM = NO/MO

Substitute the values for known things and x for MO

We get

10/18 = 4/x

Or cross multiply to get

10x=72

x=7.2

So answer is 7.2

3 0
3 years ago
What does A equal? Plz help, I will mark brainliest ASAP!!!
xz_007 [3.2K]

Answer:

57. i hope this helps

6 0
3 years ago
Read 2 more answers
A= 1/1 bh solve for h
8_murik_8 [283]

\text{Hello there!}\\\\\text{Solve for h:}\\\\A=\frac{1}{1}bh\\\\\text{Multiply both sides by 1}\\\\A=1bh\\\\\text{Divide both sides by 1b}\\\\\frac{A}{1b}=h\,\,or\,\,\frac{A}{b}=h\\\\\boxed{h=\frac{A}{b}}

4 0
4 years ago
The midpoint of AB is M(1, -4). If the coordinates of A are (-3,-6), what are the coordinates of B?
kramer

Answer:

The coordinates of B is (5,-2)

Step-by-step explanation:

In order to find the coordinates of B, you have to use midpoint formula. Then substitute the following values into the formula :

m = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} )

Let (x1,y1) be A (-3,-6),

Let (x2,y2) be B,

Let midpoint be M (1,-4),

(1, - 4) =  (\frac{ - 3 + x2}{2} , \frac{ - 6 + y2}{2} )

by \: comparison, \:

\frac{ - 3 + x2}{2}  = 1

- 3 + x2 = 2

x2 = 5

\frac{ - 6 + y2}{2}  =  - 4

- 6 + y2 =  - 8

y2 =  - 2

6 0
3 years ago
Step by step<br> Please urgent
kotegsom [21]

Answer:

Below in bold.

Step-by-step explanation:

1) ( a^2 + b^2 = (a + b)^2 - 2ab

= 29 - 2(6)

= 29-12

= 17.

2).  (x - y)^2 = x^2 + y^2 - 2xy

so 20 = 18 - 2xy

2xy = 18-20 = -2

xy = -1.

3). 1/x + x = 7

(1/ x + x)^2 = 1/x^2  + x^2 +x/x + x/x

= 1/x^2 + x^2 + 2

But(1/x + x)^2 = 7^2 = 49

so 1/x^2 + x^2 + 2 = 49

so 1/x^2 + x^2 = 49 - 2 = 47.

6 0
3 years ago
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