Question

Michael finds that 35 customers at his grandfather's grocery store use a coupon. To simulate the behavior of the next 5 customers, he writes the numbers 1, 2, 3, 4, and 5 on cards and mixes them up. He writes down that 1, 2, and 3 represent someone using a coupon and 4 and 5 represent someone not using a coupon. Michael then randomly selects a card, puts it back, and records the number. He repeats this 5 times to represent 5 customers or 1 trial. He repeats this experiment for a total of 15 trials. The results are shown in the table. 43454 24511 55555 43453 55315 25215 32235 43311 11154 13342 42514 13223 44215 45313 13324 Using this simulation, what is the probability that, out of the next 5 customers, 4 or more will use a coupon? Enter your answer, as a fraction in simplified form, in the box.

Answer 1

There were 5 of the 15 in the simulation that used a coupon.  To find the probability you just divide 5 by 15

P(=>4) = 5/15 = 1/3 - probability of 4 or more

Answer 2

Answer:

Hence,  the probability that, out of the next 5 customers, 4 or more will use a coupon is:

                   $\dfrac{1}{3}$

Step-by-step explanation:

Total 15 trials were recorded as follows:

43454   24511   55555  43453     55315    25215    32235      43311      11154  13342   42514    13223      44215   45313  13324

Now, we are asked to find the probability that, out of the next 5 customers, 4 or more will use a coupon.

We know that probability is the ratio of number of favorable outcomes to the total number of outcomes.

 Hence, number of favorable outcomes are: 5

(32235    43311   13342    13223   13324  )

Total number of outcomes are: 15

( Since 15 trials were performed)

Hence, Probability is:  $\dfrac{5}{15}=\dfrac{1}{3}$

 Hence, the answer is:

               $\dfrac{1}{3}$