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dybincka [34]
3 years ago
12

I NEED HELP!!!

Mathematics
1 answer:
Elena L [17]3 years ago
3 0

Answer:

D. -2,222.85

Step-by-step explanation:

87x(-25.55)=-2222.85x

Steps

87 x(-25.55)

remove parenthesis (-a)=-a

=-87x *25.55

multiply the numbers : 87 *25.55=2222.85

=-2222.85x

hope this helps lmk

your welcome and thanks (:

 

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Answer:

When we have a function g(x)

We will have a maximum at x when:

g'(x) = 0

g''(x) < 0.

Now we start with:

g(x) = 3*x^4 - 8*x^3

The first derivation is:

g'(x) = 4*3*x^3 - 3*8*x^2

g'(x) = 12*x^3 - 24*x^2

We can rewrite this as:

g'(x) = x^2*(12*x - 24)

Now we want to solve:

g'(x) = 0 =  x^2*(12*x - 24)

We have one trivial solution, that is when x = 0.

The other solution will be when the term inside of the parentheses is equal to zero.

Then we need to solve:

12*x - 24 = 0

12*x = 24

x = 24/12 = 2

Then g'(x) is equal to zero for x = 0, and x = 2.

Notice that both of these points are included in the interval [ -2,2 ]

Now we need to look at the second derivative of g(x):

g''(x) = 3*12*x^2 - 2*24*x

g''(x) = 36*x^2 - 48*x

Ok, now we need to evaluate this in the two roots we found before:

if x = 0:

g''(0) = 36*0^2 - 48*0 = 0

g''(0) = 0

Then we do not have a maximum at x = 0, this is a point of inflection.

if x = 2:

g''(2) = 36*(2^2) - 48*2 = 48

then:

g''(2) > 0

This is an absolute minimum.

Now let's look only at the interval [ -2,2 ]

We know that:

g''(0) =  0

g''(2) > 0

Then at some point, we should have g''(x) < 0 in our interval.

We need to find the first point such that happens, so let's try with the lower limit of the interval but with the first derivation, if g'(x) < 0, this means that the function is decreasing from that point on, then that point will be a maximum in our interval.

x = -2

g'(-2) = (-2)^2*(12*-2 - 24) = -192

And if we look at the function:

g'(x) = x^2*(12*x - 24)

We can easily see that it is negative unitl x = 0, and then it keeps being negative until x = 2.

So in the interval  [ -2,2 ], the function g'(x) is always negative or zero, this means that in the interval  [ -2,2 ], the function g(x) is always decreasing or constant.

Then the absolute maximum of g(x) in the interval  [ -2,2 ]  will be  x = -2

this means that:

g(-2) ≥ g(x) for all x ∈  [ -2,2 ]

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Answer: The experiment is blinded because the volunteers in both groups are unaware of which dog food they received.

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Ike Phillips worked 6.7 hours at time-and-a-half pay and 3.4
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Working out the different pay rates earned by Ike Phillips :

  • Time and half pay rate = $17.055
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Let :

Regular rate = $11.37

Total earning for the week = $454.80

Double pay hours = 3.4

Time and half pay hours = 6.7

  • Time and half pay rate = 1.5 × regular pay rate = 1.5 × 11.37 = $17.055

  • Double pay rate = 2 × regular pay rate = 2 × 11.37 = $22.74

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  • Double rate earning = rate × time = $22.74 × 3.4 = $77.316

  • Gross earning = (regular + time and half + double earning) = $(454.80+114.2685+77.316) = $646.3845

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Select the ordered pairs that are located 8 units away from the point (2.1).<br><br> Plssss help
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The ordered pairs that are located 8 units away from the point (2, 1) are; (-6,1), (10,1), (2,-7) and (2,9)

<h3>Ordered pairs and Distance.</h3>

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Hence, the following pair of coordinates have x or y coordinates which are 8 units away from the x or y coordinates of the given pair of coordinates.

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