Create an equation using the formula for area of a rectangle; area = width * length
(X + 2)(x + 3) = 600
Multiply the dimensions.
X^2 + 3x + 2x +6 = 600, or simplified x^2 +5x + 6 = 600.
Subtract 600 to get the following:
X^2 + 5x - 594 = 0
Factor by x:
(X - 22)(x + 27) = 0
Solve for x
X - 22 = 0
X = 22.
Use the POSITIVE VALUE of x as you can’t have a negative area for a room.
Then substitute 22 for x to get the dimensions
(22+ 2) or 24 for length and (22+3) or 25 for width.
No solution because when you plug in the variables for x y and z none of them equal that correct number.
<span>circumference of circle = 2*pi*r
given r = 5
so circumference = 31.42
now we know 360 degree is uniformly distributed on this circumference
so x/360=10/31.42
so x= 114.65
so option C.) 114.65 is the answer</span>
Answer:
The area of sector AOB is 75.36 unit²
Step-by-step explanation:
Consider the provided information.
Circle O with minor arc AB=60 degrees and OA =12.
We need to find the area of sector.
Area of the sector: 
Substitute 
and r =12 in above formula.
Hence, the area of sector AOB is 75.36 unit²
The numbers are 9 and 27.
