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3 years ago

What is 2/3 divided by 5/6

Mathematics

1 answer:

Serjik [45]3 years ago

6 0

4/5. 2/3 divided by 5/6 is equivalent to 2/3 multiplied by 6/5, so the answer is 4/5.

You might be interested in

The function f is defined by f(x)=2.1x−1.7. Use this formula to find the following values of f.

viktelen [127]

f(c + a) = 2.1 c + 2.1 a - 1.7

f(1/3 x - 2/3) = 0.7 x - 3.1

f(x + 2) = 2.1 x + 2.5

f(3c) = 6.3 c - 1.7

Step-by-step explanation:

The function is f(x) = 2.1 x - 1.7

We need to use this formula to find

f(c + a)
f(1/3x - 2/3)
f(x + 2)
f(3c)

To solve the problem substitute x by each value in the bracket

∵ f(x) = 2.1 x - 1.7

f(c + a) means substitute x by c + a

∵ x = c + a

∴ f(c + a) = 2.1(c + a) - 1.7

- Multiply the bracket by 2.1

∴ f(c + a) = 2.1 c + 2.1 a - 1.7

∵ f(x) = 2.1 x - 1.7

- f(1/3 x - 2/3) means substitute x by 1/3 x - 2/3

∵ x = 1/3 x - 2/3

∴ f(1/3 x - 2/3) = 2.1(1/3 x - 2/3) - 1.7

- Multiply the bracket by 2.1

∴ f(1/3 x - 2/3) = 0.7 x - 1.4 - 1.7

- Add the like terms

∴ f(1/3 x - 2/3) = 0.7 x - 3.1

∵ f(x) = 2.1 x - 1.7

- f(x + 2) means substitute x by x + 2

∵ x = x + 2

∴ f(x + 2) = 2.1(x + 2) - 1.7

- Multiply the bracket by 2.1

∴ f(x + 2) = 2.1 x + 4.2 - 1.7

- Add the like terms

∴ f(x + 2) = 2.1 x + 2.5

∵ f(x) = 2.1 x - 1.7

- f(3c) means substitute x by 3c

∵ x = 3c

∴ f(3c) = 2.1(3c) - 1.7

- Multiply 2.1 by 3c

∴ f(3c) = 6.3 c - 1.7

Learn more:

You can learn more about the functions in brainly.com/question/628130

#LearnwithBrainly

3 0

3 years ago

10 points, please help me and explain how to do this with answers!

8_murik_8 [283]

$\bf f(x)=log\left( \cfrac{x}{8} \right)\\\\
-----------------------------\\\\
\textit{x-intercept, setting f(x)=0}
\\\\
0=log\left( \cfrac{x}{8} \right)\implies 0=log(x)-log(8)\implies log(8)=log(x)
\\\\
8=x\\\\
-----------------------------$

$\bf \textit{y-intercept, is setting x=0}\\
\textit{wait just a second!, a logarithm never gives 0}
\\\\
log_{{ a}}{{ b}}=y \iff {{ a}}^y={{ b}}\qquad\qquad 
% exponential notation 2nd form
{{ a}}^y={{ b}}\iff log_{{ a}}{{ b}}=y 
\\\\
\textit{now, what exponent for "a" can give you a zero? none}\\
\textit{so, there's no y-intercept, because "x" is never 0 in }\frac{x}{8}\\
\textit{that will make the fraction to 0, and a}\\
\textit{logarithm will never give that, 0 or a negative}\\\\
$

$\bf -----------------------------\\\\
domain
\\\\
\textit{since whatever value "x" is, cannot make the fraction}\\
\textit{negative or become 0, , then the domain is }x\ \textgreater \ 0\\\\
-----------------------------\\\\
range
\\\\
\textit{those values for "x", will spit out, pretty much}\\
\textit{any "y", including negative exponents, thus}\\
\textit{range is }(-\infty,+\infty)$
p, li { white-space: pre-wrap; }

----------------------------------------------------------------------------------------------

now on 2)

$\bf f(x)=\cfrac{3}{x^4}$ if the denominator has a higher degree than the numerator, the horizontal asymptote is y = 0, or the x-axis,

in this case, the numerator has a degree of 0, the denominator has 4, thus y = 0

vertical asymptotes occur when the denominator is 0, that is, when the fraction becomes undefined, and for this one, that occurs at $x^4=0\implies x=0$ or the y-axis

----------------------------------------------------------------------------------------------

now on 3)

$\bf f(x)=\cfrac{1}{x}$

now, let's see some transformations templates

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\

\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\mathbb{R}^{{{ B}}x+{{ C}}}+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}
\end{array}$

now, let's take a peek at g(x)

$\bf \begin{array}{lcllll}
g(x)=&-&\cfrac{1}{x}&+3\\
&\uparrow &&\uparrow \\
&\textit{upside down}&&
\begin{array}{llll}
\textit{vertical shift up}\\
\textit{by 3 units}
\end{array}
\end{array}$

3 0

3 years ago

What is the range of the function y=square root x+5 ?

Ne4ueva [31]

Answer:

all non-negative real numbers, [0, ∞)

Step-by-step explanation:

Replacing x in the parent function √x with (x+5) shifts the graph horizontally, but has no effect on the vertical extent of the graph. It still ranges from 0 to +∞.

The range of √(x+5) is [0, ∞).

4 0

3 years ago

The formula FC +32 changes a temperature reading from the Celsius scale C to the Fahrenheit scale F What is the temperature meas

kirill115 [55]

°F = (9/5) °C + 32

°F = (9/5) 20° + 32

°F = 68

7 0

2 years ago

Simplify. (-4-7i)-(5-6i)

Drupady [299]

1) Simplify

-4-7i-(5-6i)

2) Simplify brackets

-4-7i-5+6i

3) Collect like terms

(-4-5)+(-7i+6i)

4) Simplify

-9-i

Your answer is -9-i

6 0

3 years ago

Read 2 more answers