Answer:
We must prove that (c+a)(c+d) = (b+c)(b+d)
- Let us use principles from mathematical induction
- a=bx , b=cx, c=dx
- a+c = b + c
- c +d = b + d
- Such that (a+c)(c+d)=(b+c)(b+d)
Rate positively and give brainlist
okay so first we need to multiply 160 on both sides
{18/32(160)=n/160*160 (160 cancels out)}
so once we finish our calculations on the left side we get n equals 90
{n=90}
5(-11)+4(3)^2 = -19
The answer is -19
Same strategy as before: transform <em>X</em> ∼ Normal(76.0, 12.5) to <em>Z</em> ∼ Normal(0, 1) via
<em>Z</em> = (<em>X</em> - <em>µ</em>) / <em>σ</em> ↔ <em>X</em> = <em>µ</em> + <em>σ</em> <em>Z</em>
where <em>µ</em> is the mean and <em>σ</em> is the standard deviation of <em>X</em>.
P(<em>X</em> < 79) = P((<em>X</em> - 76.0) / 12.5 < (79 - 76.0) / 12.5)
… = P(<em>Z</em> < 0.24)
… ≈ 0.5948
Your answer would be - 3/10
