3.75 ÷ 1.50 is equivalent to 375 ÷ 150.<br> The dividend and divisor were both multiplied by

A line passing through the points (6,-2) and (-2,4). Complete the work shown

Marrrta [24]

Answer:

2.5

Step-by-step explanation:

3 0

3 years ago

50 random teenagers were asked how many hours a day they use their phone. They spent an average of 7 hours a day with a standard

tatyana61 [14]

Answer:

The margin of error for the true mean number of hours a teenager spends on their phone is of 0.4 hours a day.

Step-by-step explanation:

We have the standard deviation of the saple, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 50 - 1 = 49

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2\frac{1.3}{\sqrt{50}} = 0.4$

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for the true mean number of hours a teenager spends on their phone is of 0.4 hours a day.

4 0

3 years ago

In a casino in Blackpool there are two slot machines (machine 1 and machine 2): one that pays out 10 % of the time, and one that

otez555 [7]

Answer:

Given that;

a)

2 machines, 1 and 2

Machine 1

pays 10% of times when the machine is generous

So the probability that the machine 1 pays given that its generous is

P (Pays/machine 1 is generous) = 10% = 0.10

Machine 2

pays 20% of times when its generous

i.e the probability that the machine pays given that its generous is;

P (Pays / machine 2 is generous) = 20% = 0.20

Also we assume there is equal chance of being generous

i.e

P(machine 1 is generous) = P(machine 2 is generous ) = 0.5

b)

this is to help obtain the probability that machine 1 is generous given that the player loose in the first bet,

i.e P(machine 1 is generous / lost)

c)

Since, the probability that the machine is generous is 0.5,

it can be said that there is 50% chance that machine 1 is generous when the player loses the first bet

d)

therefore The required probability is calculated as;

P(machine 1 is generous/lost) = p(machine 1 is generous ∩ lost) / p (lost)

= [p(lost/machine 1 is generous) × p(machine 1 is generous)] / [{(1-p(pays/machine 1 is generous)) × p(machine 1 is generous)} + {((1-p(pays/machine 2 is generous)) × p(machine 2 is generous)}]

= [(1 - p(pays/machine 1 is hereous)) × p(machine 1 is generous)] × [(( 1- 0.10) × 0.5) + ((1 - 0.20) × 0.5)]

= ( 1- 0.10) × 0.5) / 0.85

= 0.5294

so the probability that the player loses the first bet given that the machine is generous is 0.5294

e)

Since the gotten probability that the player loses the first bet given that machine 1 is generous is close to 0.50 then it can be said that the probability is consistent with the expectations.

5 0

4 years ago

HELP<br> i suck at this and dont understand so its really helpfull if you explain it

xxTIMURxx [149]

Answer:add the area of all 3 faces then label them length width height then use the formula SA=2lw+2lh+2hw, and u wil get ur awnser

Step-by-step explanation:

hopefully this helps

8 0

2 years ago

PLEASE HELPP!!!!!!!!!!!!

Sergeeva-Olga [200]

Answer:

2) the graph has a positive slope. the slope is 15. the y-intercept is 50.

3) (4,110)

7 0

3 years ago

3.75 ÷ 1.50 is equivalent to 375 ÷ 150. The dividend and divisor were both multiplied by