Answer and Explanation:
Number of classes = 8
Highest value =2300
Lowest value = 1250
Class width= highest value – lowest value / number of classes
= 2300 – 1250/8
= 131.25 = 132
So, we can write class as 1250+132=1382
Class frequency
1250-1382 2
1382-1514 3
1514-1646 6
1646-1778 2
1778-1910 3
1910-2042 2
2042-2174 1
2174-2306 1
Answer:
the answer is 10
Step-by-step explanation:
f(2) that means the value of x= 2
the substitute x=2 in the 4(2)+2.Replace x with 2
A. The
y-intercept (b) of a linear equation is obtained when x = 0. Therefore from the
given table,
y - intercept
= 8
Since at
time zero the displacement is 8 ft, this means that the horse was already
outside the barn initially.
B. The
average rate of change of the function represents the slope of the linear
equation (m). This can be calculated using the formula:
average rate
of change = m = (y2 – y1) / (x2 – x1)
m = (158 –
58) / (3 – 1)
m = 50
<span>C. Since we have determine the y-intercept and
the slope, we can formulate the linear equation:</span>
y = m x + b
y = 50 x + 8
The domain
is the value of x. When y = 508, x is equivalent to
508 = 50 x +
8
<span>x = 10 hrs</span>
B=t-am is the correct answer:)
