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3 years ago

Which point is in the solution set of this system inequalities?

Mathematics

1 answer:

Basile [38]3 years ago

4 0

Answer:

Step-by-step explanation:

To find which ordered pairs are solutions to the inequalities we can simply plug in the x and y values of the ordered pairs into the inequalities and if the equation is true for both inequalities then the ordered pair is a solution to the inequalities.

For (0,0)

x = 0

y = 0

y > x + 5

Substitute 0 for y and x

0 > 0 + 5

Simplify right side

0 > 5

The inequality is not true as 5 is greater than 0, not less than. So immediately we can eliminate answer choice A.

For (5,1).

x = 5

y = 1

y > x + 5

Substitute 5 for x and 1 for y

1 > 5 + 5

Simplify right side

1 > 10

Again, the equation is not true as 1 is not greater than 10. This means that c cannot be the answer

For (3,7)

x = 3

y = 7

y > x + 5

Substitute 3 for x and y for 7

7 > 3 + 5

Simplify right side

7 > 8

7 is not greater than 8 meaning that (3,7) cannot be a solution to the inequalities

None of the ordered pairs created true equations hence the answer is B

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The lengths of sides of a right triangle are 16 meters, 30 meters, and 34 meters. The triangle is dilated by a scale factor of 4

konstantin123 [22]

Answer:

Step-by-step explanation:

to be honest you guy should just use photo math its faster and i you dont need to pay to get answer

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3 years ago

What is the distance between (-6,4) and (-8,6)? Choose 1 answer:

lukranit [14]

Answer:

Step-by-step explanation:

We want to find the distance between (-6, 4) and (-8, 6).

We can use the distance formula given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Let (-6, 4) be (x₁, y₁) and let (-8, 6) be (x₂, y₂).

Substitute:

$d=\sqrt{(-8-(-6))^2+(6-4)^2$

Evaluate:

$d=\sqrt{(-2)^2+(2)^2$

Evaluate:

$d=\sqrt{4+4}=\sqrt{8}$

Hence, our answer is D.

6 0

3 years ago

Are these two lines parallel, perpendicular or neither? y = -1/3x - 5 y = 1/3x + 2

Thepotemich [5.8K]

Parallel because they have the same slope

8 0

3 years ago

please help. answer is 62.1m(squared) and the objects are composite! please show the work, no matter what i do i cant seem to ge

yuradex [85]

Answer:

$SA=62.1\ m^2$

Step-by-step explanation:

step 1

Find the surface area of the smaller rectangular prism

$SA=2B+Ph$

where

B is the area of the base

P is the perimeter of the base

h is the height of the prism

$SA=2[(2.5)(1.5)]+2(2.5+1.5)(1.5)$

$SA=7.5+12=19.5\ m^2$

step 2

Find the surface area of the cube

$SA=6s^2$

where

s is the length side of the cube

$SA=6(2.5^2)=37.5\ m^2$

step 3

Find the lateral area of the cylinder

$LA=\pi DL$

where

D is the diameter of the base

L is the length of cylinder

$LA=(3.14)(0.5)(3.5)=5.495\ m^2$

step 4

Find the area of the base of cylinder

$A=\pi r^{2}$

we have

$r=0.5/2=0.25\ m$ ----> the radius is half the diameter

$A=(3.14)(0.25)^{2}=0.19625\ m^2$

step 5

Find the surface are of the composite figure

we know that

The surface area of the composite figure is equal to the surface area of the smaller rectangular prism plus the lateral area of the cylinder, plus the surface area of the cube, minus the area of the two bases of cylinder

$SA=19.5+5.495+37.5-2(0.19625)=62.1\ m^2$

5 0

3 years ago

Write the solution to the inequality in set - builder notation: 5r + 8 < 63

Leni [432]

First, the inequality needs to be solved. The first step is to subtract 8 from both sides of the inequality, leading to 5r < 55. Dividing 5 out from both sides, this will leave r < 11. Next, to form a set notation, the inequality is written in such form: {r | r < 11}.

7 0

3 years ago