The line to find: y = mx + b
the line perpendicular to y= 2/5x+6/6 so it has the slope m × 2/5 = -1
thus the slope m = -5/2
the line passes through the point (-2,6) so:
6 = (-5/2)×(-2) + b so b = 1
the equation of the line is y = -5/2x +1
F1 . . . 100% of it = 900N is in the +x direction.
F2 . . . 70.7% of it (cos45°, 530.3N) is in the +x direction,
and 70.7% of it (sin45°, 530.3N) is in the +y direction.
F3 . . . 80% of it (520N) is in the -x direction,
and 60% of it (390N) is in the +y direction.
Total x-component: 900 + 530.3 - 520 = 1,950.3 N
Total y-component: 530.3 + 390 = 920.3 N
Magnitude of the resultant = √ (x² + y²)
= √(1950.3² + 920.3²)
= √4,650,070.09
= 2,156.4 N .
Angle of the resultant, measured counterclockwise
from the +x axis, is
tan⁻¹ (y / x)
= tan⁻¹ (920.3 / 1950.3)
= tan⁻¹ (0.4719)
= about 25.3° .
Caution:
The same fatigue that degrades my ability to READ the question accurately
may also compromise the accuracy of my solutions. Before you use this
answer for anything, check it, check it, check it !
