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melisa1 [442]
3 years ago
10

It cost Mila $5.00 to send 125 text messages. What is the cost of sending text messages, in dollars per text?

Mathematics
1 answer:
Marina CMI [18]3 years ago
6 0

Answer:

0.04 dollars per text

Step-by-step explanation:

5 dollars divided by 125 texts is equal to 0.04 dollars per text. SO just do 5/125 to get your answer

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What is 1 million times 4358
adelina 88 [10]

Answer:

What is 1 million times 4358

Step-by-step explanation:

You add 6 zeros on the end since million has 6 zeroes.

6 0
3 years ago
Write an algebraic expression: 4 groups of y.
Dvinal [7]
4y is your answer because ffor is the mathmatical term for multiplying in any word problem. 
8 0
2 years ago
Read 2 more answers
So I have another trigonometry question PLZ HELP ME I'm clueless at this rate I have like a little idea but I'm lost, SO PLZZZ!
Sergio039 [100]

Answer:

1) The windsurfer is approximately 580 ft from each lifeguard stand.

2) The distance between the Earth and Mercury is approximately 61 million miles.

Step-by-step explanation:

The image other two situations described is presented in the attached image to this answer.

1) From the attached image, the windsurfer forms a right angled triangle with each of the lifeguard stand and the midpoint between the two lifeguard stands.

Hence, the angle at the top of the triangle is half of 30°, 15° and the distance from the midpoint of the lifeguard stands to the lifeguard stands is 300/2 = 150 ft.

Let the required distance of the windsurfer from each of the lifeguard stands be x.

Using trigonometric relations,

Sin 15° = (150/x)

x = 150 ÷ sin 15° = 150 ÷ 0.2588

x = 579.6 ft = 580 ft to the nearest whole number

2) From the image, the Sun, Earth and Mercury form a triangle.

Let the possible distance between the Earth and Mercury be y.

Using cosine rule,

y² = 36² + 93² - (2×36×93×cos 22°)

y² = 3,736.5769098208

y = √3,736.5769098208 = 61.13 million miles = 61 million miles to the nearest million miles.

Hope this Helps!!!

5 0
3 years ago
What is the length of the diameter of a circle inscribed in a right triangle with the length of hypotenuse c and the sum of the
jeyben [28]

Answer:

  diameter = m - c

Step-by-step explanation:

In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).

The sum of the lengths of the tangents from points A and B on side "c" is ...

  (b-r) +(a-r) = c

  (a+b) -2r = c

Now, the problem statement defines the sum of side lengths as ...

  a+b = m

and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...

  m -d = c

  m - c = d . . . . add d-c

The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.

5 0
3 years ago
Simplify −45(30x−40)+(42x+4) . Write your answer in factored form.
kakasveta [241]

solution

-4(327x-451)

5 0
2 years ago
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