The total number of all possible options is 40 (17 + 3 + 8 + 12) and number of options that fit the description of blue or large is 28 ( 17 + 3 + 8). Probability is represented as the number of desired options over the number of total options. This means the probability of a blue or large is 28 / 40 = 7 / 10.
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Let's simplify step-by-step.
5x^3 + 3 + 2x^3 − x^2 + 1
= 5x^3 + 3 + 2x^3 + −x^2 + 1
Combine Like Terms:
= 5x^3 + 3 + 2x^3 + −x^2 + 1
= ( 5x^3 + 2x^3 ) + ( −x^2 ) + ( 3 + 1 )
= 7x^3 + −x^2 + 4
Answer:
= 7x^3 − x^2 + 4
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Answer:
the sum is -4
Step-by-step explanation:
Answer:
D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.
Step-by-step explanation:
We will test the hypothesis on the difference between means.
We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).
Then, the difference between means is:

If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:

The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.
This is approximately 2 standards deviation (z=2).
The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.