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lukranit [14]
3 years ago
15

Which expression represents the distance between −14.6 and −5.2 on the number line?

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
4 0
Hello! To answer this question, all you have to do is subtract both numbers from each other. 14.6 - 5.2 is 9.4. The numbers are 9.4 units away from each other on a number line. An expression that would represent a distance between them are 14.6 - 5.2 = x. Just make the negative numbers positive to make it easier to solve.
CaHeK987 [17]3 years ago
3 0

Answer:

9.4

Step-by-step explanation:

We are given that two integers -14.6 and -5.2

We have to find  distance between -14.6 and -5.2.

Difference between =-5.2-(14.6)

Difference=-5.2+14.6=9.4

Distance is the absolute value of 9.4

Therefore,

\mid 9.4\mid =9.4

Distance between -14.6 and -5.2 is 9.4

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3 years ago
Algebra 1 :
victus00 [196]

What we have been given here are two points.

f(3) = -4 is the same as (3, -4)

f(2) = 6 is the same as (2, 6)

We can then use these two points to find the equation of a line.

Step 1: Find the slope

Slope Formula: (y2 - y1) / (x2 - x1)

Slope = (6 - - 4) / (2 - 3) = (10) / (-1) = -10

Step 2: Find the y-intercept

To find the y-intercept, we'll take our slope and one of our points and plug them into slope-intercept form, then solve for b.

Slope-Intercept Form: y = mx + b

Point = (2, 6)

6 = 2(-10) + b

6 = -20 + b

b = 26

Step 3: Create the equation of the line

Now that we have the slope and y-intercept, all that's left to do is plug both of those values into slope-intercept form.

y = -10x + 26

Answer: y = -10x + 26

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3 0
2 years ago
2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

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3 years ago
Read 2 more answers
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<h2>f = -5</h2><h3></h3><h3>f(x) = 4x - 9</h3><h3>Add 9 to both sides</h3><h3>f(x) + 9 = 4x</h3><h3>Divide x from both sides</h3><h3>f + 9 = 4</h3><h3>Subtract 9 from both sides</h3><h3>f = -5</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>
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3 years ago
Figure ABCDE is similer to figure FGHIJ, AB=16, CD=10 and EA=12. What is the measure of HI?
Likurg_2 [28]
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