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lions [1.4K]
4 years ago
12

A red candle is 8 inches tall and burns at a rate of 7/10 inch per hour. a blue cans is 6 inches tall and burns at a rate of 1/5

inch per hour. after how many hours will both candles be the same height whats the answer
Mathematics
1 answer:
kap26 [50]4 years ago
3 0

Set it up as a function:

Y = 8 - (7/10)x

Y = 6 - (1/5)x


Y is the height.

Set the equations equal to each other and solve for x.


8 - (7/10)x = 6 - (1/5)x

8 - (5/10)x = 6

- (1/2)x = 6 - 8

-(1/2)x = -2

x=4 hours


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You are laying an asphalt driveway. How much surface area must you cover if the driveway is 19 feet long and 10.5 feet wide?
Scorpion4ik [409]

Assuming that your driveway is rectangular, just mult. the length and width together to get the area:

(19 ft)(10.5 ft) = 199.5 ft^2

C is the correct answer choice.


7 0
3 years ago
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Please help me on this i don’t get it that well
NeX [460]

Answer:

13.75

Step-by-step explanation:

make a ratio between the original lengths, 11 : 5.5

then put the ratio of the enlarged lengths, 27.5 : __

now you divide 27.5 by 11 to find how many times you multiplied the lengths, 2.5.

now you multiply 5.5 by 2.5 giving you the answer of 13.75

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4 years ago
At what rate per annum ci will RS 2000 amount to RS 2315.35 in 3 years
Mashutka [201]

<u>ANSWER: </u>

Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%

<u>SOLUTION: </u>

Given,  

P = RS 2000

C.I = RS 2315.35

T = 3 years

We need to find the rate per annum. i.e. R = ?

We know that,  

When interest is compound Annually:

Amount $=\mathrm{P}\left(1+\frac{\mathrm{R}}{100}\right)^{n}$

Where p = principal amount

r = rate of interest

n = number of years

$2315.35=2000 \times\left(1+\frac{R}{100}\right)^{3}$

$\left(1+\frac{R}{100}\right)^{3}=\frac{2315.35}{2000}$

$\left(1+\frac{R}{100}\right)^{3}=1.157$

$1+\frac{R}{100}=\sqrt[3]{1.157}$

$1+\frac{R}{100}=1.0500$

$\frac{R}{100}=1.05-1$

$\frac{R}{100}=0.05$

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Hence, rate per annum is 5 percent.

3 0
3 years ago
Solving equations and distributive property
Serhud [2]

Answer:

The answer is 10

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5 0
3 years ago
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If a particular set of data is approximately normally distributed, we would find that approximately A) 2 of every 3 observations
Kryger [21]

Answer:

A) No

B) No

C) Yes

Step-by-step explanation:

A)  2 out of three observations is equal to

2/3  = 0.67    or  67 %

We know tha the interval

[μ  -  σ/2 ,  μ + σ/2]  is approximately 68.3 % of the values

Therefore 2 out of 3 would not fall in that interval

B)

4 out of  5   is  4/5    = 0,8     or 80 %  If we  examine the interval

[μ  -  σ ,  μ + σ ]   which is approximately 95. Then value 4/5  ( 0,8)

Therefore 0,8 is out of the interval

C) 19/20 = 0,95     or 95 % is almost exact the value for the interval

[μ  -  1.5σ ,  μ + 1.5σ ]  That value is inside  μ - 2σ , μ + 2

8 0
3 years ago
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