Surface area of a box dimensions of 16 18 and 14
1 answer:
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There are two ways to equate a straight line. We first have y=mx+b. Then, we have (y-y₁)=m(x-x₁). Both work fine and have similar variables, but the numbers are mixed around a bit. Your equation clearly shows the second form of equation. As our equation has x-x₁ on the right, we can notice that x+1 must mimic that, so x+1=(x-x₁). As x-(-1)=x+1, we can only assume that x is -1. Looking at the points given to us, y must be -2, so we have y-(-2)=y+2, so 2 fills in the leftmost open box. To find the slope, or m, we must take
from points (x₁, y₁) and (x₂, y₂). It doesn't matter which point is (x₁, y₁) , but it matters that the y₁ corresponds to the x₁. Thus, we have our slope as
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Option C:
x = 90°
Solution:
Given equation:
<u>To find the degree:</u>
Subtract 1 + cos²x from both sides.
Using the trigonometric identity:
Let sin x = u
Factor the quadratic equation.
u + 2 = 0, u – 1 = 0
u = –2, u = 1
That is sin x = –2, sin x = 1
sin x can't be smaller than –1 for real solutions. So ignore sin x = –2.
sin x = 1
The value of sin is 1 for 90°.
x = 90°.
Option C is the correct answer.