Answer:
The minimum score required for admission to the nearest whole number = 557
Step-by-step explanation:
We solve this using z score formula.
z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
Top 30% of the candidates is a ranking that is equivalent to = 100 - 30% = 70th percentile.
The z score of 70th percentile = 0.524
Mean = 497
Standard deviation of 114.
Minimum score = raw score = ???
Hence:
0.524 = x - 497/114
Cross Multiply
0.524 × 114 = x - 497
59.736 = x - 497
x = 59.736 + 497
x = 556.736
The minimum score required for admission to the nearest whole number = 557
