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wariber [46]
4 years ago
8

Use the quadratic formula to solve x-6x+8=0

Mathematics
1 answer:
Sedbober [7]4 years ago
6 0

x  = [-(-6) +/- sqrt((-6)^2 - 4*1 * 8))] / 2

   =  (6 + sqrt4) / 2 ,  ( 6 - sqrt4)/2

  =  4 , 2
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If Andrea traveled 300 miles in 5 hours at what rate was she driving?
vladimir1956 [14]

Answer:

60 mph

Step-by-step explanation:

For this problem, we are looking at the rate, miles per hour. We know that Andrea traveled 300 miles in 5 hours, but how many miles did she travel in one hour? Let's do the math:

300÷5=60 miles.

So, in one hours, Andrea travels 60 miles. We get the rate, 60mph.

<u>Andrea was driving at 60 mph.</u>

<u />

<em>I hope this helps! Please let me know if you have any questions :)</em>

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3 years ago
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Find the greatest four digits number which is divisible by 12, 18 and 30.​
Fudgin [204]

Answer:

The answer would be 8100

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Find the value of the expression below when x = 27, y = - 4 , and z = 64 . 2 * root(3, x) - 5sqrt(x) + y ^ 2 answer
Anna71 [15]

Answer:

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Step-by-step explanation:

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<u>Expression:</u>

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3 0
3 years ago
If A * B is defined as (A + B)/AB, compute (2 * 6) * (3 * 4)
Bad White [126]

Answer:

144

Step-by-step explanation:

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What are the dimensions of the matrix?
DerKrebs [107]

Answer:

  • The dimensions of a matrix are the number of rows × the number of columns of the matrix.
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Explanation:

<em>The dimensions of a matrix</em> is the number of rows × the number of columns of the matrix.

Your matrix is garbled. Thus, to help you I will work with an hypothetical matrix.

Assume the matrix:

        \left[\begin{array}{cccc}1&0&0&0\\2&4&0&3\\0&0&0&9\end{array}\right]

That matrix has four colums and 3 rows.

For instance, the first colum is:

            \left[\begin{array}{c}1\\2\\0\end{array}\right]        Thus, it has 4 columns.

And the second row is:

          \left[\begin{array}{cccc}2&4&0&3\end{array}\right]         Thus, it has 3 rows.

Hence,  the matrix is 3 × 4.

The first number is the number of rows and the second number is the number of columnns.

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