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3 years ago

PLEASE HELP ITS URGENT how can you use an equation to make a prediction from a pattern?

1 answer:

4 0

An equation can be used to predict values from a pattern by merely substituting any value to determine the equivalent value. An example is the geometric series which has a standard equation of an = a1 * r^(n-1) and is used to predict the nth term of the series

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The segments shown below could form a triangle.

Shalnov [3]

Answer:

Step-by-step explanation:

Condition for a triangle formed by three segments,

Sum of two segments should be greater than third segment

1). AC + BC > AB

2). AC + AB > BC

3). AB + BC > AC

1). AC + BC > AB

1 + 8 > 8

9 > 8

Triangle is possible.

2). AC + AB > BC

1 + 8 > 8

9 > 8

Triangle is possible.

3). AB + BC > AC

8 + 8 > 1

16 > 1

Triangle is possible.

Therefore, with the help of given segments triangle can be formed.

Answer is TRUE.

8 0

2 years ago

Find the solutions of the quadratic equation 3x^2-5x+1=0.

Black_prince [1.1K]

Answer:

The solutions of the quadratic equation are $x_{1} = \frac{5 + \sqrt{13}}{6}, x_{2} = \frac{5 - \sqrt{13}}{6}$

Step-by-step explanation:

This is a second order polynomial, and we can find it's roots by the Bhaskara formula.

Explanation of the bhaskara formula:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

For this problem, we have to find $x_{1} \text{and} x_{2}$ .

The polynomial is $3x^{2} - 5x +1$ , so a = 3, b = -5, c = 1.

Solution

$\bigtriangleup = b^{2} - 4ac = (-5)^{2} - 4*3*1 = 25 - 12 = 13$

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-5) + \sqrt{13}}{2*3} = \frac{5 + \sqrt{13}}{6}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a} = \frac{-(-5) - \sqrt{13}}{2*3} = \frac{5 - \sqrt{13}}{6}$

The solutions of the quadratic equation are $x_{1} = \frac{5 + \sqrt{13}}{6}, x_{2} = \frac{5 - \sqrt{13}}{6}$

3 0

3 years ago

Kite ABCD is reflected over the line y = x. What rule shows the input and output of the reflection, and what is the new coordina

Svetach [21]

The answer:

according to the image the coordinates of pre image are:

A(-7, 2), B(-5, 3) C(-2, 2) and D(-5, 1)

<span>Kite ABCD is reflected over the line y = x, the main rule to find the coordinates of the images is (y, x)

for example if A(-7, 2) the image A' is A'(2, -7)

the answer is </span><span>(x,y)→(y,x); A' is at (2, −7)</span>

4 0

3 years ago

Read 2 more answers

Find the simple interest paid on a loan of $4,750 at a rate of 19.5% for 30 months.

Kazeer [188]

Answer:

Monthly Payment $201.31

Total Interest Paid $1,289.26

Total Paid $6,039.26

Step-by-step explanation:

8 0

2 years ago