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Inga [223]
3 years ago
14

Find the common ratio and an explicit form in each of the following geometric sequences.

Mathematics
1 answer:
Margaret [11]3 years ago
7 0

Answer:

The explicit form is a_{n}=162(2/3)^{n-1}

Step-by-step explanation:

The explicit form of a geometric sequence is given by:

a_{n}=ar^{n-1}

where an is the nth term, a is the first term of the sequence and r is the common ratio.

In this case:

a=162

The value of the common ratio is obtained by dividing one term by the previous term.

For the first and second terms:

108/162=2/3

For the second and third terms (In order to prove that 2/3 is the common ratio)

72/108=2/3

Therefore:

r=2/3

Replacing a and r in the formula:

a_{n}=162(2/3)^{n-1}

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laila [671]
Hi, this is the notation for inclusion of all real numbers.

x \in \mathbb{R}

We can also state numbers which are positive or negative with a sign on top of the R notation like so:

x \in \mathbb{R}^{+} \text{ or } x \in \mathbb{R}^{-}
7 0
3 years ago
Answer is 60. Plz step by step explanation !! I'm in urgent !! Thank you​
Aleks04 [339]

Answer:

60°

Step-by-step explanation:

ABCO is a parallelogram (opposite sides are parallel).

AO is equal to the radius of the circle, so BC must also equal the radius.

CO is equal to the radius of the circle, so AB must also equal the radius.

If we draw a line from O to B, we split the parallelogram into two triangles.  Since OB is equal to the radius of the circle, each triangle is an equilateral triangle.  Therefore, angle A is 60°.

8 0
4 years ago
Approximately how long is a leg of an isosceles right triangle that has a hypotenuse of length 11.31
Lapatulllka [165]

Answer:

Leg of an isosceles right triangle is 7.99 long.

Step-by-step explanation:

Given:

Length of the hypotenuse =11.31

To find:

Length of the leg of an isosceles right triangle =?

Solution:

According to Pythagorean's Theorem, we have

a^2 +b^2 = c^2-----------------------------(1)

Here were are given as isosceles triangle, so the two sides will be of same length

So equation 1 can be rewritten as

a^2 +a^2 = c^2

2a^2 = c^2

Substituting the value of hypotenuse

2a^2 = (11.31)^2

2a^2 = 127.91

a^2 = \frac{127.91}{2}

a^2 =63.955

a = \sqrt{63.955}

a = 7.99

7 0
3 years ago
How do I solve this problem?
lidiya [134]
B = A(1+\frac{i}{n})^{nt}
A = 47900
i = 5% = .05
n = number of compounding periods in a year (1,2,12,365)
t = number of years = 5
4 0
3 years ago
Solve for x: 3(x-3)+5=32
4vir4ik [10]

Answer:

Use a calculator its easier

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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