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Sonja [21]
2 years ago
7

A principal of 5350 is placed in an account that earns 3.5% interest. If the interest is compounded annually, how much money wil

l be in the account at the end of 4 years
Mathematics
1 answer:
harina [27]2 years ago
6 0
5350 x 3.5% = 187.25

187.25 is compounded per year

187.25 x 4 = 749.00 is the interest after 4 years

749.00 + 5,350 = 6,099

6,099 will be in the account at the end of 4 years.
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The answer is 152

Step-by-step explanation:

When you have a number in between 9999 and 1000 you can divide by 10 to get ten percent of the number

3 0
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The cable television company reduced taxes 20% last year. If the original service cost $20.50 what is the new cost
blondinia [14]
.2 * 20.50 = 4.1

20.50 + 4.1 = $24.60
5 0
3 years ago
Which sequences are geometric? <br><br> Check all that apply.
andre [41]

Answer:

3, 12, 48, 192, ...

3, 15, 75, 375, ...

2, 10, 50, 250, ...

8 0
3 years ago
Simplify the following expression.
Rzqust [24]

Step-by-step explanation:      

<u>Step 1: Add the numbers: 9.5 +6.2 = 15.7</u>

=8.6\left(15.7-3.5^2\right)

3.5^2=12.25

=8.6\left(15.7-12.25\right)

<u>Step 2: Subtract the numbers: 15.7 - 12.25 = 3.45</u>

= 3.45X 8.6

<u>Step 3: Multiply the numbers: 8.6 × 3.45 = 29.67</u>

<u />=29.67<u />

<u />

- To solve this equation, the first step is to add the numbers 9.5 + 6.2 into the equation and it will lead to 15.7 as the number for step one.

- To solve this equation, the second step is to subtract the numbers 15.7 - 12.25 into the equation and it will lead to 3.45 as the answer.

- To solve this equation, the third step is to multiply the numbers 8.6 x 3.45 into the equation and it will lead 29.67 as the final answer for the whole equation.

Answer:      

=29.67

 

Hope this helps.

3 0
2 years ago
solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars
Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

  • Every x has only one value of y
  • x appears once in ordered pairs

<u><em>Examples:</em></u>

  • The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
  • The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
  • The domain is the set of values of x
  • The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0
2 years ago
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