The weight of the new student is 27 kg.
Average weight
= total weight ÷total number of students
<h3>
1) Define variables</h3>
Let the total weight of the 35 students be y kg and the weight of the new student be x kg.
<h3>2) Find the total weight of the 35 students</h3>
<u>
</u>
y= 35(45)
y= 1575 kg
<h3>3) Write an expression for average weight of students after the addition of the new student</h3>
New total number of students
= 35 +1
= 36
Total weight
= total weight of 35 students +weight of new students
= y +x
<h3>4) Substitute the value of y</h3>
<h3>5) Solve for x</h3>
36(44.5)= 1575 +x
1602= x +1575
<em>Subtract 1575 from both sides:</em>
x= 1602 -1575
x= 27
Thus, the weight of the new student is 27 kg.
Answer:
It would be constant.
Step-by-step explanation:
Since there is no x value, the line will have no slope and just be horizontal about y= -2.
Answer:
(0,1)
Step-by-step explanation:
The equation for slope is y=mx+b.
The b value stands as the y - intercept.
New cordinates are formed by adding 7 in x and subtracting 2 from y
A(−2, 2) =A ' (-2 +7 , 2 - 1 ) = A' (5,1)
B(−2, 4) = B' (-2 + 7 , 4 -1 )= B' (5,3)
C(2, 4) = C' (2 + 7 , 4 -1 )= C' (9,3)
<span>D(2, 2) D' (2 + 7 , 2 -1 ) = D' ( 9 , 1)</span><span>
</span>
Answer: C. 10.2
Step-by-step explanation: because in decimal form 10.19803902 to the nearest is 10.2
