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vampirchik [111]
3 years ago
6

Let P= {8, 9, 10, 11, 12), Q = {9, 10, 11), and R = {5, 6}.Find P∪O.​

Mathematics
1 answer:
Degger [83]3 years ago
5 0
PUQ= {8,9,10,11,12} is the answer
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Please find it <br>please help ​
Sedbober [7]

Answer:

29/30

Step-by-step explanation:

11/12 + 1/20

220+12/240

232/240 ........divide it by 8

29/30

6 0
3 years ago
Tracy needs to find the length and width of the equipment room where she works. The room is 2 meters longer than it is wide. The
Alekssandra [29.7K]

Answer:

The answer to your question is: width = 3 meters

Step-by-step explanation:

Data

Perimeter = 16 meters

The room is 2 meters longer than its width, then   length = width + 2

Perimeter = 2 length + 2 width

   16 =  2(width + 2) + 2 width

    16 = 2 width + 4 + 2 width

   16 = 4 width +4

   16 - 4 = 4 width

    12 = 4 width

    12/4 = width

     3 = width  

length = 3 + 2 = 5 meters

8 0
3 years ago
150 students were surveyed on how many text messages to send in a date for different devices. let X represent the number of stud
kakasveta [241]

Given that the total number of students that sent messages = 150 students

a) To obtain the equation to represent the number of students who send text messages, we will sum up the variables in the Venn diagram and equate it to 150.

\begin{gathered} 75+x+3x+x=150 \\ x+3x+x=150-75 \\ 5x=75 \end{gathered}

Hence, the equation is

5x=75

b) Solving for x

\begin{gathered} 5x=75 \\ x=\frac{75}{5}=15 \\ \therefore x=15 \end{gathered}

Therefore, x = 15.

c) The total number of student that uses cell phone = 75 + x = 75 + 15= 90students

The total number of students that sent messages = 150students

The formula for probability is,

\text{Probability = }\frac{\text{Number of students that uses cell phone}}{\text{Total number of students}}

Hence,

P(\text{Number of students that uses cell phone)}=\frac{90}{150}=\frac{3}{5}

Therefore, the probability that a randomly chosen student uses their cell phone to send text messages ​is 3/5.

7 0
2 years ago
Instructions: Factor 715 as a product of primes.
Drupady [299]

Answer:

{1, 5, 143}

Step-by-step explanation:

715 is evenly divisible by 5, so one factor of 715 is 5 and the next is 715/5, or 143.  143 is not factorable further.  Thus, the factors of 715, in ascending order, are 1, 5 and 143.

8 0
4 years ago
. If there are 60 green M&amp;M’s in a bag, how many orange M&amp;M’s will be in the bag?
AveGali [126]

Answer:

I feel stu pid but is it none?

Step-by-step explanation:

6 0
3 years ago
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