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stealth61 [152]
3 years ago
13

I NEED HELPPPPP!!!!!!!!!!!!

Mathematics
1 answer:
malfutka [58]3 years ago
7 0
The answer would be number 3.

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The high temperature one day was -1 °F. The low temperature was -5 °F. What was the difference between the high and low temperat
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2 years ago
Need help please, does any one know how to do this​
ziro4ka [17]

Answer:

  • (6-u)/(2+u)
  • 8/(u+2) -1
  • -u/(u+2) +6/(u+2)

Step-by-step explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

  (-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

  (6 -u)/(u +2)

__

2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

  -(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

or

  8/(u+2) -1

Of course, anywhere along the chain of equal signs the expressions are equivalent.

__

3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

__

4) You can also multiply numerator and denominator by some constant, say 3:

  -(3u -18)/(3u +6)

You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

  (1+x^2)(6 -u)/((1+x^2)(u+2))

7 0
3 years ago
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