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victus00 [196]
2 years ago
8

How is graphing (3, 0) different from graphing (0, 3)?

Mathematics
1 answer:
podryga [215]2 years ago
8 0

Answer:

X-axis

Y-axis

Step-by-step explanation:

(x, y)

The x-axis moves horizontally, the y axis moves vertically.

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Veronica is choosing between two health clubs. After how many months will the total cost for each health club be the​ same? Yoga
sergiy2304 [10]

Answer:

14.02

Step-by-step explanation:

You'd have to write equations for the price per month for each club.

Let  x  equal the number of months of membership, and  y  equal the total cost.

Club A's is  y = 24x + 21.50 and Club B's is  y = 17.25 x + 41.00 Because we know that the prices,  y , would be equal, we can set the two equations equal to each other.

24x + 21.50 =17.25 x+ 41.00

subtract 21.50 both sides

. We can now solve for  x  by isolating the variable.

24x=17.25x+19.5

divide 17.25x

1.39x=19.5

divide 1.39 both sides

x=14.02

After five months, the total cost would be the same.

4 0
3 years ago
Help plsss Show me the work plsss
velikii [3]

Answer:

a) y = 6x - 3

b) 1/3y = 2x -1

The first thing you need to do is isolate (y) in the second equation

3 x (1/3y) = 3 x (2x - 1)

y =6x - 3

After isolating (y) in equation b they end up being the same.

Graphing:

In order to graph this, you have to make the first point at (0, -3) since this is the Y-intercept of the equation.

In order to graph the other points, you must move 6 units up and 1 unit to the right. Or vise versa If you need a visual I'll gladly link one.

5 0
3 years ago
HELP PLEASEEEEE!!!!!!! IN NEED THE ANSWER LIKE YESTERDAY
uranmaximum [27]

Answer is 214

Step-by-step explanation:

because if you add them it equal that number

4 0
3 years ago
3x+3y=6 and 5x-6y=15
Anna71 [15]
Multiply first equaton by 2 and add to the other equation

6x+6y=12
<u>5x-6y=15 +</u>
11x+0y=27

11x=27
divide both sides by 11
x=27/11


sub back
3x+3y=6
divide both sides by 3
x+y=2
(27/11)+y=2
2 and 5/11+y=2
minus  2 and 5/11 both sides
y=-5/11

x=27/11
y=-5/11
(27/11,-5/11)
7 0
3 years ago
at noon joice drove to the lake at 30 mi. per hour, but she made a long walk back at 4 mi. per hour. how long did she walk ifshe
Kryger [21]
Distance = 30 mph * time
distance = 4 mph * time

distance = 30 mph * t
distance = 4 mph * (17-t)

Since distance is equal then
30 mph * t = 4 mph * (17-t)
 
30t = -4t + 68

34t = 68

t = 2 hours

We see the return trip time is (17 -t ) which is 15 hours.
The beginning trip time is 2 hours.

Double Check
Beginning trip = 30 miles * 2 = 60 miles
Return trip = 4 miles * 15 = 60 miles.


3 0
3 years ago
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