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4 years ago

Hey can you please help me posted picture of question

Mathematics

1 answer:

Kamila [148]4 years ago

7 0

To find x- intercepts
y = 0
(x+4)(x-2)=0
x+4=0 or x-2 = 0
x = -4 or x = 2

And the vertex will be (-1,-9)

The correct option is (B)

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Me pueden ayudar porfa

xz_007 [3.2K]

Answer:

same question bro

Step-by-step explanation:

7 0

3 years ago

Solve this for Brainliest! See the attachment [Level - GCSE]

madreJ [45]

Answer:

$x = 3 + 4\sqrt{3}$

Step-by-step explanation:

OPQ is a right angle triangle.

Using Pythagoras

$x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0$

Using quadratic formula

$x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}$

$x = 3 + 4\sqrt{3} = 9.928(4s.f.)$

$x = 3 - 4\sqrt{3} = -3.928(4s.f.)$ (Length can't be negative)

∴ $x = 3 + 4\sqrt{3}$

3 0

2 years ago

Read 2 more answers

Find the minimum, maximum, and range for the given set of data.

serg [7]

The answer is option C

7 0

3 years ago

Read 2 more answers

All the items on the sale rack were 75 percent off their original price.

tresset_1 [31]

Answer:

112 $ is the original price

Step-by-step explanation:

$x \times 0.75 = 84 \\ x = 84 \div 0.75 \\ x = 112$

you have to think that the original price multiplied by 0.75 (also known as 75%) gave the result of what he saves i.e 84 $. So we put up an equation with the original price multiplied by 75% which equals the 84 $ he saved on buying that item on sale

4 0

3 years ago

The area of the region in the first quadrant between the graph of y = k*sin(x) and x-axis (where k > 0 ) on the closed interv

astraxan [27]

Note that $0\le k\sin x\le k$ in the given closed interval, so the area is exactly given by the definite integral

$\displaystyle\int_0^\pi k\sin x\,\mathrm dx$

(no absolute values needed!)

Integrating gives

$-k\cos x\bigg|_{x=0}^{x=\pi}=-k(\cos\pi-\cos0)=-k(-1-1)=2k$

8 0

3 years ago