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Anastasy [175]
3 years ago
10

What is the value of each expression (-3)2

Mathematics
1 answer:
k0ka [10]3 years ago
5 0

First you had to remove parenthesis first.

-3*2=-6

Multiply by the numbers.

3*2=6

Final answer \boxed{=-6}

6/3=2

2*3=6

6/2=3

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

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50 points!!! Basic math!
tangare [24]

Formula for the area of the triangle:

1/2 bh

b = base

h = height

#6.

Area = 36 in²

Base = 18 in

36 = 1/2(18)h

36 = 9h

36 ÷ 9 = h

4 = h

height = 4 in

#7.

Area = 2 ft²

Height = 1 ft

2 = 1/2 b (1)

2 = 1/2 b

2 ÷ 1/2 = b

4 = b

Base = 4 ft

#8.

Area = 42 in²

Base = 12 in

42 = 1/2 (12) h

42 = 6h

42 ÷ 6 = h

7 = h

Height = 7 in

Notice that the answers have no exponents (²). That is because they are used only on the area of shapes as units.

Since you find the area by multiplying things together, for example x · x = x², the exponent is there.

You do not need to worry about this being in the calculation. This will just be in units such as:

cm²

ft²

in²

m²

Just remember to use these exponents in the units for the areas.

7 0
3 years ago
Read 2 more answers
A graph of x^2 + y^2 = 9 is shown on the grid. By drawing the line x + y = 2, solve the equations x^2 +y^2 =9. x + y = 2
Hatshy [7]

Answer:

Step-by-step explanation:

8 0
2 years ago
I really need help with this. Can anyone help me please?
I am Lyosha [343]

Answer:

f(x)=(x-3)(x^2+4x+8)

Step-by-step explanation:

A polynomial function is given by the form:

f(x)=a(x-p)(x-q)...

Where a is the leading coefficient, and <em>p</em> and <em>q</em> are the roots (more can be added if necessary).

Our zeros are 3 and (-2 + 2i).

And our leading coefficient <em>a </em>= 1.

Furthermore, by the Complex Root Theorem, if (-2 + 2i) is a zero, then (-2 - 2i) must also be a zero.

So, by substitution, we acquire:

f(x)=1(x-(3))(x-(-2+2i))(x-(-2-2i))

Simplify:

f(x)=(x-3)(x+2-2i)(x+2+2i)

Expand the second and third factors:

\begin{aligned} &=(x+2-2i)x+(x+2-2i)(2)+(x+2-2i)(2i)\\&= (x^2+2x-2ix)+(2x+4-4i)+(2ix+4i-4i^2)\\&=(x^2)+(2x+2x)+(-2ix+2ix)+(-4i+4i)+(4-4i^2)\\&=x^2+4x+(4+4)\\&=x^2+4x+8    \end{aligned}

Therefore, our polynomial function of least degree and the given zeros will be:

f(x)=(x-3)(x^2+4x+8)

6 0
2 years ago
What is the equation in slope-intercept from of the line that passes through the point (3, 1) and is parallel to the line repres
Murljashka [212]
Parallel = same slope
Y = 2.4x + b
Plug in the point to find b
1 = 2.4(3) + b
1 = 7.2 + b
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2 years ago
Max puts a stopper in the bathtub and turns on the faucet at t = 0.
Marysya12 [62]

Answer:

D

Step-by-step explanation:

6 0
3 years ago
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