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boyakko [2]
4 years ago
5

Find the number of real number solutions for the equation. x^2-3x+8=0

Mathematics
2 answers:
melamori03 [73]4 years ago
7 0

Answer:

None.

Step-by-step explanation:

The coefficients are a=1, b=-3, c=8, so the discriminant is ...

... b²-4ac = (-3)²-4(1)(8) = 9-32 = -23

This negative value means both the roots are complex.

sattari [20]4 years ago
4 0

x^2-3x+8=0 \\\\\Delta=(-3)^2-4\cdot1\cdot8=9-32=-23

\Delta therefore, there are no real solutions.

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