Question

Find the number of real number solutions for the equation. x^2-3x+8=0

Answer 1

Answer:

None.

Step-by-step explanation:

The coefficients are a=1, b=-3, c=8, so the discriminant is ...

... b²-4ac = (-3)²-4(1)(8) = 9-32 = -23

This negative value means both the roots are complex.

Answer 2

$x^2-3x+8=0 \\\\\Delta=(-3)^2-4\cdot1\cdot8=9-32=-23$

$\Delta$ therefore, there are no real solutions.