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Julli [10]
4 years ago
7

Veronica loves to create creative things. She can make 5 craft pieces in 5 days. On the basis of a contract she has to make 20 p

ieces of crafts. How many days will she take?
Mathematics
2 answers:
algol134 years ago
6 0

Answer:

It will take  20 days

Step-by-step explanation:

First we must get the rate of craft made per day.

Veronica make 5 craft pieces in 5 days

Rate= 5 craft pieces/5 days

Rate=1 craft pieces/days

If we want to know how many days will take to make 20 craft pieces. We use the ratio

20 craft pieces/1 craft pieces/days= 20 days

Mashutka [201]4 years ago
5 0
It will take 20 days to make 20 craft pieces. 


If she can make 5 in 5 days, then it will take her 20 days to make 20 craft peices
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An equation is formed of two equal expressions. The value of the constant of proportionality is 0.41.

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An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given there exists a proportional relationship between the number of juice bottles bought, j, and the total cost in dollars and cents. Therefore,

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As the relation is represented by the equation c=0.41j. Therefore, the value of the constant of proportionality is 0.41.

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2 years ago
You’re given two side lengths of 3 centimeters and 5 centimeters. Which measurement can you use for the length of the third side
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Answer:

You could use a measurement of 4 centimeters.

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Step-by-step explanation:

The third side must either be less than 3+5, that is less than 8 cms and  it must be greater than (5-3) = 2 cms. If it is any other length we could not construct a triangle.

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The value of 2^3 + 3^3 = ___. Numerical Answers Expected!
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Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips.Urn II contains three red
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Answer:

P(R_{2}) =\frac{10}{15} = 0.667

Step-by-step explanation:

Step 1: Understanding the possible events

Selecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be completed in two ways:

A. Selecting a red chip from Urn I and adding it to Urn II and then selecting a red chip from Urn II

B. Selecting a white chip from Urn I and adding it to Urn II and then selecting a red chip from Urn II

Therefore total probability is:

                                         P(R_{2}) = P(A) + P(B)

Step 2: Probability of selecting either chip from Urn I

Urn I contains 2 reds and 4 white chips, that gives a total of 6 chips.

                                             P(R_{1}) = \frac{2}{6} =\frac{1}{3}

                                             P(W_{1}) = \frac{4}{6} =\frac{2}{3}

Step 3: Probability of selecting a red chip from Urn II

Urn II originally contains 3 reds and 1 white chip, that gives a total of 4 chips.

Remember: Once a chip is added from Urn I to Urn II the total number of chips will increase in the Urn II

Case 1: When a red chip is added from Urn I to Urn II

Red chips    = 4

White chips = 1

Total Chips  = 5

                                                  P(R_{2_1}) = \frac{4}{5}

Case 2: When a white chip is added from Urn I to Urn II

Red chips    = 3

White chips = 2

Total Chips  = 5

                                                  P(R_{2_2}) = \frac{3}{5}

Therefore the total Probability of selecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be calculated as:

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                           P(R_{2}) = P(R_{1}) . P(R_{2_1}) + P(W_{1}) . P(R_{2_2})

                                           P(R_{2}) =\frac{1}{3} . \frac{4}{5}  + \frac{2}{3} .\frac{3}{5}

                                             P(R_{2}) =\frac{4}{15}  + \frac{2}{5}

                                            P(R_{2}) =\frac{10}{15} = 0.667      

8 0
3 years ago
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