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My name is Ann [436]

4 years ago

12

The Mitchell family is making payments on the refrigerator, which is a cost of $984. If they pay $41 every month, how many month

s will it take to pay for the refrigerator?

2 answers:

Aleksandr [31]4 years ago

6 0

I think you have to divide 984 and 41 which gets you 24

tino4ka555 [31]4 years ago

6 0

24 months or in other words 2 years
$41-1 month
$82
$123 and so on

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Given a set of digits (1, 2, 3, 4, 5, 6, 7, 8, 9}

Yuki888 [10]

Answer:the attached file shows the solution

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3 years ago

For each of the systems of equations that follow, use Gaussian elimination to obtain an equivalent system whose coefficient matr

noname [10]

Answer:

b) inconsistent

d) inconsistent

f) inconsistent

j) X_1 = 2 - 6a , X_2 = 4 + a , X_3 = 3 - a, X_4 = a (free variable)

Step-by-step explanation:

b)

Given: Augmented matrix

$\left[\begin{array}{ccc}2&-3&5\\-4&6&8\end{array}\right]$

Row operation : R_2 + 2*R_1

$\left[\begin{array}{ccc}2&-3&5\\0&0&18\end{array}\right]$

Looking at R_2 : 0 not equal to 18 ; Hence, inconsistent

c)

Given: Augmented matrix

$\left[\begin{array}{cccc}3&2&-3&4\\1&-2&2&1\\11&2&1&14\end{array}\right]$

Row operation : R_2 <---> R_1

$\left[\begin{array}{cccc}1&-2&2&1\\3&2&-3&4\\11&2&1&14\end{array}\right]\\$

Row operations : R_2 - 3*R_1 & R_3 - 11*R_1

$\left[\begin{array}{cccc}1&-2&2&1\\0&8&-9&1\\0&24&-21&3\end{array}\right]\\$

Row operations : R_3 - 3*R_2

$\left[\begin{array}{cccc}1&-2&2&1\\0&8&-9&1\\0&0&6&0\end{array}\right]\\$

Looking at R_3 : 0 not equal to 6 ; Hence, inconsistent

f)

Given: Augmented matrix

$\left[\begin{array}{cccc}1&-1&2&4\\2&3&-1&1\\7&3&4&7\end{array}\right]\\$

Row operations : R_2 - 2*R_1 & R_3 - 7*R_1

$\left[\begin{array}{cccc}1&-1&2&4\\0&5&-5&-7\\0&10&-10&-21\end{array}\right]\\$

Row operations : R_2 --> ( 1 / 5 )* R_2 & R_3 --> ( 1 / 10 )* R_3

$\left[\begin{array}{cccc}1&-1&2&4\\0&1&-1&-1.4\\0&1&-1&-2.1\end{array}\right]\\$

Row operations : R_3 - R_1

$\left[\begin{array}{cccc}1&-1&2&4\\0&1&-1&-1.4\\0&0&0&-0.7\end{array}\right]\\$

Looking at R_3 : 0 not equal to -0.7 ; Hence, inconsistent

j)

Given: Augmented matrix

$\left[\begin{array}{ccccc}1&2&-3&1&1\\-1&-1&4&-1&6\\-2&-4&7&-1&1\end{array}\right]\\$

Row operations : R_2 + R_1 & R_3 + 2*R_1

$\left[\begin{array}{ccccc}1&2&-3&1&1\\0&1&1&0&7\\0&0&1&1&3\end{array}\right]\\$

corresponding equations are:

X_1 + 2*X_2 - 3*X_3 + X_4 = 1

X_2 + X_3 = 7

X_3 + X_4 = 3

Free parameter : X_4 = a , then:

X_3 = 3 - a

X_2 = 4 + a

X_1 = 1 - a + 3*(3 - a) - 2*(4 + a) = 2 - 6 a

4 0

4 years ago

Simplify: (2x2 − 9x + 3) + (−7x2 + 4x − 2)

Leokris [45]

Combine like terms
2x^2 + -7x^2 = -5x^2
-9x + 4x = -5x
3 + -2 = 1
put back together
-5x^2 - 5x +1

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3 years ago

What is 6/12 in simplest form

Tatiana [17]

6/12 in simplest form = ?

Divide numerator and denominator by GCF.
GCF = 6

6/12
6 ÷ 6 = 1
12 ÷ 6 = 2
1/2

6/12 = 1/2

6/12 in simplest form is 1/2

5 0

3 years ago