Answer:
answer is a . x²-8x+16=32
x²-8x=32-16
Answer:
m ∠RMK = 51°
Step-by-step explanation:
m ∠JMK = m ∠RMK + m ∠JMR
10x + 19 = 7x - 26 + 6x + 12
10x +19 = 13x -14
19 = 3x -14
33 = 3x
11 = x
m ∠RMK = 7(11) - 26 = 51°
m ∠JMR = 6 (11) + 12 = 78
Answer:

General Formulas and Concepts:
Order of Operations: BPEMDAS
Midpoint Formula: 
Step-by-step explanation:
<u>Step 1: Define points</u>
J (4, 6)
K (0, -4)
<u>Step 2: Find midpoint</u>
- Substitute:

- Add/Subtract:

- Divide:

Answer:
-15
Step-by-step explanation:
Given:
The expression is:

It leaves the same remainder when divided by x -2 or by x+1.
To prove:

Solution:
Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).
Let the given polynomial is:

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that
...(i)
Substituting
in the given polynomial.


Substituting
in the given polynomial.



Now, substitute the values of P(2) and P(-1) in (i), we get




Divide both sides by 3.


Hence proved.