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dlinn [17]
3 years ago
11

Find the quotient of 812.30 divided by 83. Round to the nearest tenth.

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0
812.30/83 = 9.78674698.....
Nearest tenth means one number under decimal place so...

812.30/83 ~ 9.8

Explanation: The 9.7... rounded up to 9.8 because the number after the tenths place (in this case the number after the 7) is greater or equal to 5.
You might be interested in
A bird has a mass of 26 g and perches in the middle of a stretched telephone line. (a) Show that the tension in the line can be
Semmy [17]

Answer:

a) is demonstrated below, b) T=1.462N, c) T=14.6N

Step-by-step explanation:

a) Refer to the attached diagram.

Since the bird is standing in the middle of the line and each half is a straight line, Ta=Tb, so we will call the tension T=Ta=Tb and Tay=Tby

By trigonometry Tay=Ta·Sinθ

Since the system is in equilibrium W=Tay+Tby then:

W=2·Tay=2·Ta·Sinθ=2·T·Sinθ

Since W=mg, being m the mass of the bird and g, gravity:

mg=2TSin\theta

Isolating T, we demonstrate that

T=\frac{mg}{2Sin\theta}

b) Replacing θ=5º, m=0.026kg and g=9.8m/s² in the last equation, we can get the tension in Newtons:

T=\frac{0.026*9.8}{2Sin5}=1.462N

c) With θ=0.5º

T=\frac{0.026*9.8}{2Sin0.5}=14.6N

7 0
3 years ago
If a couple plans to have 6 ​children, what is the probability that there will be at least one boy​? Assume boys and girls are e
lutik1710 [3]

Answer:

a) \frac{63}{64}

b) The probability for the couple to be very confident that they will get at least one boy in 6 ​children is 98.43%

Step-by-step explanation:

The probability of having a boy or girl is 0.5

A couple plans to have 6 children

Probability of having at least one male child

1- (0.5)^6\\

On solving the above term, we get -

1- (\frac{1}{2})^6\\= 1-\frac{1}{64}\\ = \frac{63}{64}

The probability for the couple to be very confident that they will get at least one boy in 6 ​children is

\frac{63}{64}* 100\\ = 98.43

Thus, the probability is very high

7 0
3 years ago
Sara borrowed $5,000 from her father at a simple interest rate of 12.5% per year. Over a two - year period, she made equal month
Olin [163]

The formula for simple interest is:

A = P(1+rt)

Where P = amount borrowed

r = interest rate

t = time of loan


A = 5000(1 + 0.125*2)

A =6,250

The total amount she paid back was $6,250


For her monthly payment divide total paid back by 24 months ( 2 years = 24 months)


6250 / 24 = 260.42


Her monthly payment was $260.42

8 0
3 years ago
Read 2 more answers
The security cameras were mounted at the corners of a triangular parking lot. Camera 1 was 151 ft from camera 2, which was 122 f
Elena L [17]
Answer: Camera 3 covers the largest angle

---------------------------------------------------------------------------------
---------------------------------------------------------------------------------

Explanation:

Refer to the diagram shown in the attachment
Let
A = position of camera 1
B = position of camera 2
C = position of camera 3

We need to find the angle values for A, B and C

Notice how
a = distance from camera 2 to camera 3 (B to C) 
a = 122
the little 'a' is opposite the big 'A'

Also notice that
b = distance from camera 1 to camera 3 (A to C)
b = 139
the little b is opposite the big B

Also notice that 
c = distance from camera 1 to camera 2 (A to B)
c = 151
the little c is opposite the big C

So in summary so far we have
a = 122
b = 139
c = 151
we will use these values in the sections below
Make sure your calculator is in degree mode

----------------------------------

Use the law of cosines to find the measure of angle A
a^2 = b^2 + c^2 - 2*b*c*cos(A)
122^2 = 139^2 + 151^2 - 2*139*151*cos(A)
14884 = 19321 + 22801 - 41978*cos(A)
14884 = 42122 - 41978*cos(A)
14884 - 42122  = 42122-41978*cos(A)-42122
-27238  = -41978*cos(A)
-41978*cos(A) = -27238
-41978*cos(A)/(-41978) = (-27238)/(-41978)
cos(A) = 0.64886369050455
arccos(cos(A)) = arccos(0.64886369050455)
A = 49.544016303819
-----------------------------
Use law of cosines to find angle B
b^2 = a^2 + c^2 - 2*a*c*cos(B)
139^2 = 122^2 + 151^2 - 2*122*151*cos(B)
19321 = 14884 + 22801 - 36844*cos(B)
19321 = 37685 - 36844*cos(B)
19321 - 37685  = 37685-36844*cos(B)-37685
-18364  = -36844*cos(B)
-36844*cos(B) = -18364
-36844*cos(B)/(-36844) = (-18364)/(-36844)
cos(B) = 0.498425795244816
arccos(cos(B)) = arccos(0.498425795244816)
B = 60.1040940123789
-----------------------------
Use law of cosines to find angle C
c^2 = a^2 + b^2 - 2*a*b*cos(C)
151^2 = 122^2 + 139^2 - 2*122*139*cos(C)
22801 = 14884 + 19321 - 33916*cos(C)
22801 = 34205 - 33916*cos(C)
22801 - 34205  = 34205-33916*cos(C)-34205
-11404  = -33916*cos(C)
-33916*cos(C) = -11404
-33916*cos(C)/(-33916) = (-11404)/(-33916)
cos(C) = 0.336242481424696
arccos(cos(C)) = arccos(0.336242481424696)
C = 70.3518896838022
-----------------------------
Or we can use a shortcut to find angle C
A+B+C = 180
C = 180-A-B
C = 180-49.544016303819-60.1040940123789
C = 70.3518896838022
-----------------------------

Summary:
angle A = 49.544016303819 degrees
angle B = 60.1040940123789 degrees
angle C = 70.3518896838022 degrees
Angle C is the largest so camera 3 sweeps out the largest angle

4 0
4 years ago
How many solutions does the equation have?<br><br> 4(z−5)+2=4z−18
ANTONII [103]
Distribute the 4:
4z - 20 + 2 = 4z - 18
Subtract 4z
-20 + 2 = -18
-18 = -18
This is true so that means there are infinite number of solutions... z could be anything!
7 0
4 years ago
Read 2 more answers
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