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frosja888 [35]
2 years ago
14

Simplify (2+3)squared-16 divided by 2

Mathematics
1 answer:
seraphim [82]2 years ago
4 0

Answer:

it would be 4.5

Step-by-step explanation:

basic explantion

step 1.    3+2 =5

step 2     5x5=25

step 3      25-16=9

step 4       9 divde by 2= 4.5

simplifyed it would be  25-16 ÷ 2

more deatialed explanation.

I added 3+2 to get 5 and i sqaured the 5 to get 25 becasue 5x5 is 25 then i took away 16 and got 9 then i divde 9 by 2 to get 4.5.  hope this helped!

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Find the quotient 7.980 divided by 0.19
Advocard [28]
The answer 7980 divided by .19 =/is 42.  
5 0
3 years ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x
Lynna [10]

ANSWER

1.39

EXPLANATION

The given quadratic equation is

0 = 2 {x}^{2}  + 3x - 8

This is the same as,

2 {x}^{2}  + 3x - 8 = 0

Comparing to

a {x}^{2}  + bx  + c = 0

We have

a=2, b=3,c=-8

Using the quadratic formula, the solution is given by:

x =  \frac{ - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a}

We substitute the values to get,

x =  \frac{ - 3\pm \:  \sqrt{ {3}^{2}  - 4(2)( - 8)} }{2(2)}

x =  \frac{ - 3\pm \:  \sqrt{ 73} }{4}

The positive root is

x =  \frac{ - 3 + \:  \sqrt{ 73} }{4} = 1.39

to the nearest hundredth.

4 0
3 years ago
Read 2 more answers
What’s the answer and give an explanation.
tino4ka555 [31]

Answer:

14 = x and 2.5 = y

Step-by-step explanation:

For ABCD - the top is 8 and the sides are 11. 11 minus 8 is 3. 11 plus 3 equals 14, that’s x.

For GHIJ - the bottom is 8 and both sides are 5.5. So 8 minus 5.5 is 2.5. That’s y.

4 0
3 years ago
Read 2 more answers
How many meters are equal to 6 kilometers? Use the pattern in the number of zeros of the product when multiplying by a power of
SSSSS [86.1K]

Answer:

6km = 6000m

standard form - 6 x 10^3

6 0
2 years ago
Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ
atroni [7]

Answer: y=Ce^(^3^t^{^9}^)

Step-by-step explanation:

Beginning with the first differential equation:

\frac{dy}{dt} =27t^8y

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

\frac{1}{y} \frac{dy}{dt} =27t^8

Multiply both sides by 'dt' to get:

\frac{1}{y}dy =27t^8dt

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt

ln(y)=27(\frac{1}{9} t^9)+C

ln(y)=3t^9+C

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)

y=e^(^3^t^{^9} ^+^C^)

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

y=e^(^3^t^{^9}^)e^C

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

y=Ce^(^3^t^{^9}^)

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8

Now check if the derivative equals the right side of the original differential equation:

(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)

Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0
2 years ago
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