Describe the object-oriented software engineering approach.
1 answer:
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Answer:
Follows are the code to this question:
import java.util.*;//import packae for user-input
public class Main//defining a class Main
{
public String[] getArray(int numString)//defining a method getArray
{
String[] name=new String[numString];//defining array of String values
Scanner in = new Scanner(System.in);// creating scanner class object for input values from user-end
for(int i=0;i<numString;i++)//defining for loop for input multiple values
{
System.out.print("Enter String Value :");//print message
name[i]=in.nextLine();//input values
}
return name;//return array values
}
public String getLongestString(String[] sArray)//defining a method getLongestString
{
int m=0,mi=0; //defining integer variables
for(int i=0;i<sArray.length;i++)//defining for loop for check the longest value in array
{
if(m<sArray[i].length())//defining if block that checks m varaible value greater then sArray length
{
m=sArray[i].length();//use m to hold sArray length
mi=i;//use max_index to hold i that is loop value
}
}
return sArray[mi];//return Longest value
}
public static void main(String[] args)//defining main method
{
Main s=new Main();//Creating object of main class
String[] n;//defining string variable n
n=s.getArray(5);//use n varaible to call getArray method and store its value
System.out.println("Longest value is: "+s.getLongestString(n));//use print method to call getLongestString method
}
}
Output:
please find attached file.
Explanation:
In the given java program code, inside the main class two method that is "getArray and getLongestString", is defined, in which the "getArray" method uses an integer variable in its parameter and inside the method, an array is defined that use a scanner class for input array value.
- In the "getLongestString" pass as a parameter and inside the method, two integer variable "m and mi" is defined that use in the loop to return the longest string value.
- In the class main method is to define that creates a class object and call the above method and use the print method to return its value.
Answer:
#include <iostream>
using namespace std;
int main() {
int k;
double d;
string s;
cin >> k >> d >> s;
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s; }
Explanation:
k is int type variable that stores integer values.
d is double type variable that stores real number.
s is string type variable that stores word.
cin statement is used to take input from user. cin takes an integer, a real number and a word from user. The user first enters an integer value, then a real number and then a small word as input.
cout statement is used to display the output on the screen. cout displays the value of k, d and s which entered by user.
First the values of k, d and s are displayed in reverse order. This means the word is displayed first, then the real number and then the integer separated again by EXACTLY one space from each other. " " used to represent a single space.
Then next line \n is used to produce a new line.
So in the next line values of k, d and s are displayed in original order (the integer , the real, and the word), separated again by EXACTLY one space from each other.
The program along with the output is attached.
