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Kaylis [27]
3 years ago
8

Briefly describe the client/server model.

Computers and Technology
1 answer:
Marina86 [1]3 years ago
6 0
The client-server model is network architecture in which each computer or process on the network is either a client or a server. The components are clients, servers and communication network. <span>1. Clients are applications that run on computers. It relies on servers for files, devices, processing power. </span> Example: Email Client Email Client is an application that enables you to send and receive e-mail <span>2. Servers are computers or processes that manage network resources:</span> Disk drives (file servers) Printers (print servers) Network traffic (network servers)  Example: Database Server is a computer system that processes database queries  <span>3. Communication Network is a networks connect clients and servers</span> <span> </span>
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"a technician claims to have crimped a patch cable according to the T568A standard on one e d and T568B on the other"
yanalaym [24]

Answer:

The technician has made a cross-over cable.

Explanation:

The network is a platform that provides two or more computers to communicate. There different types of networks, namely, local-area network (LAN), wide-area network (WAN), MAN or metropolitan-area network etc.

Devices in a network can be connected with cables (ethernet IEEE 802.3) or wirelessly (wifi IEEE 802.11a/n/g). Wiring standards are strictly followed in ethernet configuration.

Two ethernet wiring standards are T568A and T568B. The difference in both standards are the pin configuration and their position in a wire defines a cable system.

When a T568A or T568B are used on both ends of a twisted pair cable, it is called a straight-through cable. When T568A is used on one end and T568B on the other, it is called a cross-over cable.

These cable systems are used for different applications. the straight-through cable is used for connecting devices that are not the same like router to switch, switch to computer etc. The cross-over cable connects similar network devices like router to router, switch to switch etc.

3 0
3 years ago
This project is to mimic a meeting request system by checking the requesting party’s validity, and the number of people attendin
alexgriva [62]

Answer:

See explaination for the program code

Explanation:

Meeting.java

------

import java.util.Scanner;

public class Meeting {

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

final int ROOM_CAPACITY = 100;

int numPeople, diff;

String name;

System.out.println("****** Meeting Organizer ******");

System.out.print("Enter your name: ");

name = input.nextLine();

System.out.println("Welcome " + name);

do{

System.out.print("\nHow many people would attend the meeting? (type 0 to quit): ");

numPeople = input.nextInt();

if(numPeople < 0)

System.out.println("Invalid input!");

else if(numPeople != 0)

{

if(numPeople > ROOM_CAPACITY)

{

diff = numPeople - ROOM_CAPACITY;

System.out.println("Sorry! The room can only accommodate " + ROOM_CAPACITY +" people. ");

System.out.println(diff + " people have to drop off");

}

else if(numPeople < ROOM_CAPACITY)

{

diff = ROOM_CAPACITY - numPeople;

System.out.println("The meeting can take place. You may still invite " + diff + " people");

}

else

{

System.out.println("The meeting can take place. The room is full");

}

}

}while(numPeople != 0);

System.out.println("Goodbye!"); }

}

output

---

****** Meeting Organizer ******

Enter your name: John

Welcome John

How many people would attend the meeting? (type 0 to quit): 40

The meeting can take place. You may still invite 60 people

How many people would attend the meeting? (type 0 to quit): 120

Sorry! The room can only accommodate 100 people.

20 people have to drop off

How many people would attend the meeting? (type 0 to quit): 100

The meeting can take place. The room is full

How many people would attend the meeting? (type 0 to quit): 0

Goodbye!

4 0
4 years ago
A certain audio compact disc (cd) contains 783.216 megabytes of digital information. each byte consists of exactly 8 bits. when
kakasveta [241]
You are not putting the question but I can guess that it asking for the CD duration. To answer this question, you need to convert the CD capacity unit(783.216 megabyte) into megabits which were used for the cd read rate (1.4 megabits/s). The calculation would be:

CD duration: CD capacity / rate= 783.216 megabytes *(8 megabits/megabyte) / (1.4 megabits /s)= 4475.52 second or 74.6 minutes
3 0
4 years ago
Suggest ways in which web designers can use color to make a statement about the subject of a web page, a brand, or the website i
Ulleksa [173]

Hi. :")

As it is used to attract interest in advertisements, different colors can be used in order to attract attention here. Or the upper left corner technique can be used. The important contents are placed in the upper left corner. Because, in the country where I live, in the technology design class, people have always studied the upper left corner further.

Good Luck!

#Turkey

4 0
3 years ago
Write a java program to print the following series: <br>1 5 9 13 17...n terms​
andrew11 [14]

Answer:

In Java:

import java.util.*;

public class Main{

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

int n;

System.out.print("Max of series: ");

n = input.nextInt();

for(int i = 1; i<=n;i+=4){

    System.out.print(i+" ");

}

}

}

Explanation:

This declares n as integer. n represents the maximum of the series

int n;

This prompts the user for maximum of the series

System.out.print("Max of series: ");

This gets user input for n

n = input.nextInt();

The following iteration prints from 1 to n, with an increment of 4

<em> for(int i = 1; i<=n;i+=4){</em>

<em>     System.out.print(i+" ");</em>

<em>}</em>

6 0
3 years ago
Read 2 more answers
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