3 years ago

80,801 rounded to the nearest ten thousand

1 answer:

8 0

90,000 since you are rounding the whole number to ten thousand 90,000 is more closer than 80000. you have to round to the number it's asking so the rest of your answer after ten thousand should be left zero. therefore making the answer 90,000.

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The product of 2 and a number minus 9 is 13

algol13

<h3>The value of the number is equal to 11.</h3>

2x - 9 = 13

Add 9 to both sides.

2x = 22

Divide both sides by 2.

x = 11

5 0

3 years ago

Use the distributive property of multiplication to find 6×24. Hint: 24= 4+20.

Marina86 [1]

Answer:

see explanation

Step-by-step explanation:

6 × 24 ← replace 24 by 4 + 20

= 6(4 + 20) ← multiply each term in the parenthesis by 6

= 24 + 120

= 124

5 0

3 years ago

In the formula that gives the circumference of a circle, which quantity is multiplied by 21 ?

zloy xaker [14]

Answer:

Radius

Step-by-step explanation:

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3 years ago

Evan was broke didn't he got his weekly allowance but because he has a hard time saving money he spent half his weekly allowance

grin007 [14]

Answer:

$16

Step-by-step explanation:

Let his weekly allowance = x

Amount spent playing golf = x / 2

Amount earned for cleaning car = $4

Final amount at hand = $12

Mathematically ;

x/2 + 4 = 12

x/2 = 12 - 4

x/2 = 8

x = 2 * 8

x = $16

Weekly allowance = $16

8 0

3 years ago

The average test scores for a particular test in algebra was 84 with a standard deviation of 5. What percentage of the students

Delicious77 [7]

Answer:

The percentage of the students scored higher than 89% is 15.87%

Step-by-step explanation:

we are given

The average test scores for a particular test in algebra was 84

so, mean is 84

$\mu=84$

a standard deviation of 5

so,

$\sigma=5$

we have

x=89

now, we can use z-score formula

$z=\frac{x-\mu}{\sigma}$

now, we can plug values

$z=\frac{89-84}{5}$

$z=1$

now, we can use calculator

and we get

$p(z>1)=0.1587$

So,

The percentage of the students scored higher than 89% is 15.87%

8 0

3 years ago