What is the measure of the angle shown with the question mark?

The heights (in cm) and arm spans (in cm) of 31 students were measured. The association between (height) and (arm span) is shown

sergeinik [125]

Answer: Mike's arm span is 7.165 cm longer than the George's one.

Step-by-step explanation:

We have that the association between height and arm span is modeled by the equation

y = 4.5 + 0.977*x

where y is height and x is arm span.

Mike is 172 cm tall, so his arm span is:

172cm = 4.5 + 0.977*x

x = (172 - 4.5)/0.977 = 171.443 cm

and George is 165 cm tall, so his arm span is:

x = (165 - 4.5)/0.977 = 164.278 cm

Then the difference between their arm span is:

171.443cm - 164.278cm = 7.165 cm

So Mike's arm span is 7.165 cm longer than the George's one.

6 0

3 years ago

How do graphs and equations reveal information about a relationship between two quantities

fiasKO [112]

Graph and equation both shows the proportional comparison between two quantities

for example, equation y = 4x, this means, the value of 'y' will always be 4 times the value of 'x'

More complex equation such as y = 3x + 5, means that the value of 'y' equals to 5 more triples of value of 'x'

Another example is the conversion graph attached below, it shows the relationship between kilometers and miles. For example, we want to find out how many miles are in 10 kilometers, we would draw a line from the point that shows 10 km towards the graph, then across from the graph to miles, and we'd get a reading of 12 miles.

3 0

3 years ago

What is the total cost of a $56.53 meal at a restaurant after including a 17% tip?

padilas [110]

The total cost is $66.14. Hope this helps.

7 0

3 years ago

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and

mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$