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choli [55]
3 years ago
12

Need help with 8,9, and 10

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0

Answer:C B A

2222222222222222222222222222222222222222222222222222222

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Simplify. 5(22 - 9 · 2) - 2( 3 · 2 4) 7 <br> a.-99 <br> b.-83 <br> c.-75 <br> d.-71
Pachacha [2.7K]
Not completely sure on the symbols, but I think it is 5 x ( 22 - 9 x 2 ) - 2 ( 3 x 2 x 4 ) x 7 = 136. It doesn't really match the answers, so my advice is that you use a calculator for this one, or as the person/teacher who gave you the problem how to solve it.

8 0
3 years ago
(7, 1) and (x, 4); m = 3/4<br> missing value<br> 50 POINTS
Sever21 [200]

Answer:

x = 11

Step-by-step explanation:

4 - 1 / x - 7 (simplify)

3 / x - 7 = 3/4 (multiply by x - 7)

3 = 3/4 (x - 7)

3 = 3/4x - 5.25 (add 5.25 to both sides)

8.25 = 3/4x (divide both sides by 8.25)

x = 11

sub into the formula to check:

4-1 / 11 - 7

3 / 4

7 0
3 years ago
What is the value of h in this graph ?<br> F(x)= |x - h|
Misha Larkins [42]

Answer:

h=4

Step-by-step explanation:

We know that the vertex(lowest point) of |x-h| is (h, 0).

By inspection, we can see that the vertex of the graph is (4, 0).

So, the lowest point of F(x)=|x-h| is (4, 0), which means \boxed{h=4}

8 0
2 years ago
Read 2 more answers
R+q-r; use q=6,and r=2
Anastasy [175]

Answer:

so you would replace all r with 2 which is 2+q-2

then replace the q with 6 so it would be: r+6-r

combined both of these to get

2+6-2

which would equal to 6

add the 2 and the 6 to get 8

then subtract 2 to get 6

3 0
3 years ago
Read 2 more answers
Calculate the unit rate:<br>write your answer as a decimal <br><br>1/2 mile in ever 1/3 hour​
Alexandra [31]

Answer:

unit \: rate =  \frac{distance}{time}

unit rate is similar to speed / velocity:

unit \: rate =  \frac{ (\frac{1}{2} )}{ (\frac{1}{3})} \\  \\  =  \frac{1}{2}  \div  \frac{1}{3}  \\  \\  =  \frac{1}{2}  \times  \frac{3}{1}  \\  \\  = >  { \boxed{ \boxed{unit \: rate  =   \frac{3}{2}  \: miles \: per \: hour}}}

[<em>unit</em><em> </em><em>rate</em><em> </em><em>must</em><em> </em><em>have</em><em> </em><em>units</em><em> </em><em>including</em><em> </em><em>per</em><em> </em><em><</em><em>time</em><em>></em><em> </em>]

7 0
2 years ago
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