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3 years ago

I need help !!!!!!!!!!! Plz

Chemistry

1 answer:

pishuonlain [190]3 years ago

5 0

Answer: 1: B. It will speed up the reaction.

2: A. Increase the concentration of a reactant.

3: A. They act as catalysts.

4: C. A catalyst decreases the activation energy needed for a reaction.

5: D. collision theory.

Explanation: I just took the quiz:)

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Calcium Oxide will react with ammonium chloride to produce ammonia gas, water vapor, and calcium chloride. If only 16.3 g of amm

Vaselesa [24]

Answer:

%age Yield = 22.72 %

Explanation:

The balance chemical equation is as follow;

2 NH₄Cl + CaO → 2 NH₃ + CaCl₂ + H₂O

Step 1: Calculate Moles of CaO, NH₄Cl and NH₃;

CaO:

Moles = Mass / M.Mass

Moles = 112 g / 56.07 g/mol

Moles = 1.99 moles of CaO

NH₄Cl:

Moles = Mass / M.Mass

Moles = 224 g / 53.49 g/mol

Moles = 4.18 moles of NH₄Cl

NH₃:

Moles = Mass / M.Mass

Moles = 16.3 g / 17.03 g/mol

Moles = 0.95 moles of NH₃

Step 2: Calculate Limiting reagent as:

According to equation.

2 moles of NH₄Cl reacts with = 1 mole of CaO

So,

4.18 moles of NH₄Cl will react with = X moles of CaO

Solving for X,

X = 4.18 mol × 1 mol / 2 mol

X = 2.09 mol of CaO

This means that none of the given reagent is limiting reagent. They both are almost equal in number of moles.

Step 3: Calculate Theoretical Yield of NH₃ as;

According to equation.

2 moles of NH₄Cl produced = 2 moles of NH₃

So,

4.18 moles of NH₄Cl will produce = X moles of NH₃

Solving for X,

X = 4.18 mol × 2 mol / 2 mol

X = 4.18 mol of NH₃

Step 4: Calculate Percentage Yield as;

%age Yield = Actual Yield / Theoretical Yield × 100

%age Yield = 0.95 mol / 4.18 × 100

%age Yield = 22.72 %

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3 years ago

What effect does high temperature have on radish growth size?

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3 years ago

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How many molecules are there in 5H20? A.5 B.7 C.10 D.11

Ad libitum [116K]

Answer:

the answers B which is 7

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2 years ago

What is the molality of a solution

vitfil [10]

Molarity (M) is the concentration of a solution expressed as the number of moles of solute per liter of solution: Molarity (M) = moles solute. liters solution.

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2 years ago

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A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

Answer: The mass of glucose in final solution is 0.420 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

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3 years ago